itertools.chain()
should do it. It takes multiple iterables and yields from each one by one, roughly equivalent to:
def chain(*iterables):
for it in iterables:
for element in it:
yield element
Usage example:
from itertools import chain
g = (c for c in 'ABC') # Dummy generator, just for example
c = chain(g, 'DEF') # Chain the generator and a string
for item in c:
print(item)
Output:
A
B
C
D
E
F