toString()function takes the decimal, converts it
to binary and adds a “-” sign.
A zero fill right shift converts it’s operands to signed 32-bit
integers in two complements format.
A more detailed answer:
//If you try (-3).toString(2); //show "-11"
It’s in the function
.toString(). When you output a number via
If the numObj is negative, the sign is preserved. This is the case
even if the radix is 2; the string returned is the positive binary
representation of the numObj preceded by a – sign, not the two’s
complement of the numObj.
It takes the decimal, converts it to binary and adds a “-” sign.
- Base 10 “3” converted to base 2 is “11”
- Add a sign gives us “-11”
// but if you fake a bit shift operation it works as expected (-3 >>> 0).toString(2); // print "11111111111111111111111111111101"
A zero fill right shift converts it’s operands to signed 32-bit integers. The result of that operation is always an unsigned 32-bit integer.
The operands of all bitwise operators are converted to signed 32-bit
integers in two’s complement format.