You are almost there. You are using:
$result = preg_replace("((\d+))", "$0", $string);
- The regex you specify as the 1st
argument topreg_*
family of function
should be delimited in pair of
delimiters. Since you are not using
any delimiters you get that error. (
and)
are meta char in a regex,
meaning they have special meaning.
Since you want to match literal open
parenthesis and close parenthesis,
you need to escape them using a\
.
Anything following\
is treated
literally.- You can capturing the integer
correctly using\d+
. But the captured
integer will be in$1
and not$0
.$0
will have the entire match, that is
integer within parenthesis.
If you do all the above changes you’ll get:
$result = preg_replace("#\((\d+)\)#", "$1", $string);