You could serialize / Deserialize the JSON as String. Use JPA Converters, which shall automatically convert the same.
Suggest to use Jackson JAR for the same.
More Related Contents:
- How to properly use findBySomeOtherId not findById in Spring data jpa?
- org.hibernate.HibernateException: Access to DialectResolutionInfo cannot be null when ‘hibernate.dialect’ not set
- What is this spring.jpa.open-in-view=true property in Spring Boot?
- How to call a stored procedure from Java and JPA
- Spring Boot, Spring Data JPA with multiple DataSources
- Connection to Db dies after >4
- Spring Boot – Cannot determine embedded database driver class for database type NONE
- Spring Boot + JPA : Column name annotation ignored
- Deserialize Java 8 LocalDateTime with JacksonMapper
- Spring JPA @Query with LIKE
- How to prevent SQL Injection with JPA and Hibernate?
- Spring-boot: required a bean named ‘entityManagerFactory’ that could not be found
- JPA Native Query select and cast object
- JPA 2 CriteriaQuery, using a limit
- Why has javax.persistence-api been replaced by jakarta.persistence-api in spring data jpa starter?
- How to use Spring Boot with MySQL database and JPA?
- JPA Select latest instance for each item
- Does JPA support mapping to sql views?
- Java – escape string to prevent SQL injection
- Spring JPA selecting specific columns
- ImprovedNamingStrategy no longer working in Hibernate 5
- Correct use of flush() in JPA/Hibernate
- can someone please explain me @MapsId in hibernate?
- Spring Boot without the web server
- JPA – Persisting a One to Many relationship
- how to use Spring Boot profiles
- Doing an “IN” query with Hibernate
- What is the correct way to do inserts/updates/deletes in Android SQLiteDatabase using a query string?
- org.hibernate.MappingException: Could not determine type for: java.util.Set [duplicate]
- Hibernate Issue : Foreign key must have same number of columns as referenced primary key