Change your first comparison to be: if (a == b) return true; This not only catches the “both null” cases, but also “compare an array to itself” case. However, for a simpler alternative – use Arrays.equals which has overloads for each primitive type. (The implementation is very similar to yours, except it hoists the array … Read more
No, there is no especially easy way to do this. JavaScript was not made for handling low-level operations such as working directly with binary data for, say, image processing. You could use a <canvas> element to base64 encode each image, and then compare the resulting base64 strings, but this will only tell you whether or … Read more
Assuming that the dicts line up like in your example input, you can use the zip() function to get a list of associated pairs of dicts, then you can use any() to check if there is a difference: >>> list_1 = [{‘unique_id’:’001′, ‘key1′:’AAA’, ‘key2′:’BBB’, ‘key3′:’EEE’}, {‘unique_id’:’002′, ‘key1′:’AAA’, ‘key2′:’CCC’, ‘key3′:’FFF’}] >>> list_2 = [{‘unique_id’:’001′, ‘key1′:’AAA’, ‘key2′:’DDD’, … Read more
function contains($str, array $arr) { foreach($arr as $a) { if (stripos($str,$a) !== false) return true; } return false; }
OK, I’m not going to code the whole thing for you (what’s the fun in that?) but I’ll get you started. First, there are two ways to do the content comparison. The lazy/mostly right way, which is comparing the length of the files; and the accurate but more involved way, which is comparing a hash … Read more
You can use Intl.Collator or String.prototype.localeCompare, introduced by ECMAScript Internationalization API: “Ł”.localeCompare(“Z”, “pl”); // -1 new Intl.Collator(“pl”).compare(“Ł”,”Z”); // -1 -1 means that Ł comes before Z, like you want. Note it only works on latest browsers, though.
The documentation for [NSArray containsObject:] says: This method determines whether anObject is present in the receiver by sending an isEqual: message to each of the receiver’s objects (and passing anObject as the parameter to each isEqual: message). The problem is that you are comparing references to objects rather than the values of the objects. To … Read more
Here’s one implementation, but whether it is the one you are after is completely impossible to say, because you have not specified what you think the answer should be: let answer = zip(array1, array2).map {$0.0 == $0.1} That gives you a list of Bool values, true if the answer matches the right answer, false if … Read more
ArrayList remove() relies on the objects implementation of the Equal method. If no implementation has been done then the object is removed by Object‘s implementation of Equals which indeed is the pointer comparison. From the documentation on ArrayList – More formally, removes the element with the lowest index i such that (o==null ? get(i)==null : … Read more
Short answer: Equality is complicated. Detailed answer: Primitives types override the base object.Equals(object) and return true if the boxed object is of the same type and value. (Note that it will also work for nullable types; non-null nullable types always box to an instance of the underlying type.) Since newAge is a short, its Equals(object) … Read more