You could use an asymmetrical border to make curves with CSS. border-radius: 50%/100px 100px 0 0; VIEW DEMO .box { width: 500px; height: 100px; border: solid 5px #000; border-color: #000 transparent transparent transparent; border-radius: 50%/100px 100px 0 0; } <div class=”box”></div>
Let P0, P1, P2 be the control points, and Pc be your fixed point you want the curve to pass through. Then the Bezier curve is defined by P(t) = P0*t^2 + P1*2*t*(1-t) + P2*(1-t)^2 …where t goes from zero to 1. There are an infinite number of answers to your question, since it might … Read more
A Demo: http://jsfiddle.net/m1erickson/4fX5D/ It’s fairly easy to create a gradient that changes along the path: It’s more difficult to create a gradient that changes across the path: To create a gradient across the path you draw many gradient lines tangent to the path: If you draw enough tangent lines then the eye sees the curve … Read more
This approach won’t work. SVG doesn’t have conical gradients. To simulate the effect, you would have to fake it with a large number of small line segments. Or some similar technique. Update: Here is an example. I approximate the 360deg of hue with six paths. Each path contains an arc which covers 60deg of the … Read more
common problem and also answered many times DeviceInfo.isSimulator() then extension is “;deviceside=true” and BisConnection then extension is “;deviceside=false;ConnectionType=mds-public” and BesConnection then extension is “;deviceside=false” and WifiConnection then extension is “;interface=wifi” in this way specific extensions or available so this is not a good way to using extensions we have to classes 1)HttpConnectionFactory 2)HttpConnectionFactoryException just import … Read more
Use the quadratic Bézier formula, found, for instance, on the Wikipedia page for Bézier Curves: In pseudo-code, that’s t = 0.5; // given example value x = (1 – t) * (1 – t) * p[0].x + 2 * (1 – t) * t * p[1].x + t * t * p[2].x; y = (1 … Read more
I’ve written some quick-and-dirty code that estimates this for Bézier curves of any degree. (Note: this is pseudo-brute force, not a closed-form solution.) Demo: http://phrogz.net/svg/closest-point-on-bezier.html /** Find the ~closest point on a Bézier curve to a point you supply. * out : A vector to modify to be the point on the curve * curve … Read more
I needed to implement this for work as well. The fundamental concept you need to start with is that the main difference between the regular Catmull-Rom implementation and the modified versions is how they treat time. In the unparameterized version from your original Catmull-Rom implementation, t starts at 0 and ends with 1 and calculates … Read more
OK, I think I found the answer. First the solution: cov_x*s_sq is simply the covariance of the parameters which is what you want. Taking sqrt of the diagonal elements will give you standard deviation (but be careful about covariances!). Residual variance = reduced chi square = s_sq = sum[(f(x)-y)^2]/(N-n), where N is number of data … Read more