What you need is the De Casteljau algorithm. This will allow you to split your curve into whatever segments you’d like. However, since you’re dealing with just cubic curves, I’d like to suggest a slightly easier to use formulation that’ll give you a segment from t0 to t1 where 0 <= t0 <= t1 <= … Read more
Your Point position measure is off because of the integer rounding generated by the RotatePoint() method. A simple correction in the method returned value, using float coordinates, will produce the correct measure: To test it, create a Timer and register its Tick event as RotateTimerTick(): Added a rotation spin increment (see the rotationSpin Field) to … Read more
try to set android:clipChildren=”false” to the parent view
Although Pete’s post is awesomely comprehensive, I’m using this method to draw a very simple line with a little triangle at its end. // create an AffineTransform // and a triangle centered on (0,0) and pointing downward // somewhere outside Swing’s paint loop AffineTransform tx = new AffineTransform(); Line2D.Double line = new Line2D.Double(0,0,100,100); Polygon arrowHead … Read more
If you are only actually changing a small portion of the UIView’s content every time you draw (and the rest of the content generally stays the same), you can use this. Rather than redraw all the content of the UIView every single time, you can mark only the areas of the view that need redrawing … Read more
If I’ve understood your question correctly, you essentially want to work out the new size of an image once rotated, and how to position the rotated image in it’s new bitmap. The diagram hopefully helps make clear the solution. Here is a bit of pseudo code: sinVal = abs(sin(angle)) cosVal = abs(cos(angle)) newImgWidth = sinVal … Read more
Basics: HTML5 Canvas as a Non-Retained Drawing Mode Graphics API First, let us discuss the manner in which the HTML5 Canvas works. Like a real-world canvas with fast-drying oil paints, when you stroke() or fill() or drawImage() onto your canvas the paint becomes part of the canvas. Although you drew a ‘circle’ and see it … Read more
Thanks to Joe Kington for the answer! I was looking for skimage.draw.line_aa. import scipy.misc import numpy as np from skimage.draw import line_aa img = np.zeros((10, 10), dtype=np.uint8) rr, cc, val = line_aa(1, 1, 8, 4) img[rr, cc] = val * 255 scipy.misc.imsave(“out.png”, img)
Using the Google Maps API V3, create a Circle object, then use bindTo() to tie it to the position of your Marker (since they are both google.maps.MVCObject instances). // Create marker var marker = new google.maps.Marker({ map: map, position: new google.maps.LatLng(53, -2.5), title: ‘Some location’ }); // Add circle overlay and bind to marker var … Read more
In OpenGL, lines are rasterized using the “Diamond Exit” rule. This is almost the same as saying that the end coordinate is exclusive, but not quite… This is what the OpenGL spec has to say: http://www.opengl.org/documentation/specs/version1.1/glspec1.1/node47.html Also have a look at the OpenGL FAQ, http://www.opengl.org/archives/resources/faq/technical/rasterization.htm, item “14.090 How do I obtain exact pixelization of lines?”. … Read more