You are right, the link which you posted in the comment would be probably the best approach. As your question sounded interesting i tried it out. You probably did it also, but here is an snippet (for other, that may come looking) var xmlhttp = new XMLHttpRequest(); xmlhttp.open(“GET”,”data.dat”,false); xmlhttp.setRequestHeader(“Range”, “bytes=100-200”); xmlhttp.send(); console.info(xmlhttp); //–> returns only … Read more
You can use a combination of the :not and :has selectors like this $(“a.add-span”).click(function() { $(“li:not(:has(span))”).each(function(index) { $(this).append(‘<span class=”spn”>new span<\/span>’); }); }); Here is a demo http://www.jsfiddle.net/xU6fV/
A lot of your questions stem from the fact that you’re not sure how morphological image processing works, but we can put your doubts to rest. You can interpret the structuring element as the “base shape” to compare to. 1 in the structuring element corresponds to a pixel that you want to look at in … Read more
It’s very important programming skill to learn how to create a minimal, reproducible example. Your problem can be reduced to this: struct Vocabulary; fn main() { let numbers = vec![Vocabulary]; let other_numbers: Vec<Vocabulary> = numbers.iter().collect(); } Let’s look at the error message for your case: error[E0277]: a collection of type `std::vec::Vec<Vocabulary>` cannot be built from … Read more
I believe you want to use array_diff_assoc http://www.php.net/manual/en/function.array-diff-assoc.php
Two values from key => value pairs are considered equal only if (string) $elem1 === (string) $elem2 . In other words a strict check takes place so the string representations must be the same. http://php.net/manual/en/function.array-diff-assoc.php The (string) value of any array is “Array”. Thus, your call to array_diff_assoc is effectively comparing these two things: Array … Read more
PHP has no support for a SQL where sort of thing, especially not with an array of arrays. But you can do the counting your own while you iterate over the data: $count = array(); foreach($fruit as $one) { @$count[$one[‘color’]]++; } printf(“You have %d green fruit(s).\n”, $count[‘green’]); The alternative is to write yourself some little … Read more
Here is a simple and effective linear filtering strategy to remove the horizontal line artifact: Outline: Estimate the frequency of the distortion by looking for a peak in the image’s power spectrum in the vertical dimension. The function scipy.signal.welch is useful for this. Design two filters: a highpass filter with cutoff just below the distortion … Read more
As far as the filtering of the drop down is concerned. Isn’t wrapping the list of possible options in a FilteredList the best solution? MCVE: import javafx.application.Application; import javafx.application.Platform; import javafx.collections.FXCollections; import javafx.collections.ObservableList; import javafx.collections.transformation.FilteredList; import javafx.scene.Scene; import javafx.scene.control.ComboBox; import javafx.scene.control.TextField; import javafx.scene.layout.HBox; import javafx.stage.Stage; public class MCVE extends Application { public void start(Stage stage) … Read more
You can use reduce() to create new object and includes() to check if value of object exists in array. const acceptedValues = [“value1”, “value3”] const myObject = { prop1: “value1”, prop2: “value2”, prop3: “value3” } var filteredObject = Object.keys(myObject).reduce(function(r, e) { if (acceptedValues.includes(myObject[e])) r[e] = myObject[e] return r; }, {}) console.log(filteredObject)