Skipping every other element after the first [duplicate]
def altElement(a): return a[::2]
def altElement(a): return a[::2]
Beware of properties inherited from the object’s prototype (which could happen if you’re including any libraries on your page, such as older versions of Prototype). You can check for this by using the object’s hasOwnProperty() method. This is generally a good idea when using for…in loops: var user = {}; function setUsers(data) { for (var … Read more
“It would seem silly that Python would not have this kind of capability, because if not you wouldn’t be able to redefine any variable passed through a for loop if it is part of a list that is being passed through.” – That’s how most programming languages work. To allow this capability would be bad … Read more
I prefer the for loop because it also sets the scope of the iterator to just the for loop.
Try to slightly modify your code: Sub forEachWs() Dim ws As Worksheet For Each ws In ActiveWorkbook.Worksheets Call resizingColumns(ws) Next End Sub Sub resizingColumns(ws As Worksheet) With ws .Range(“A:A”).ColumnWidth = 20.14 .Range(“B:B”).ColumnWidth = 9.71 .Range(“C:C”).ColumnWidth = 35.86 .Range(“D:D”).ColumnWidth = 30.57 .Range(“E:E”).ColumnWidth = 23.57 .Range(“F:F”).ColumnWidth = 21.43 .Range(“G:G”).ColumnWidth = 18.43 .Range(“H:H”).ColumnWidth = 23.86 .Range(“i:I”).ColumnWidth = 27.43 … Read more
Use the old for loop as: for (auto it = values.begin(); it != values.end(); ++it ) { auto & value = *it; //… } With this, you’ve value as well as iterator it. Use whatever you want to use. EDIT: Although I wouldn’t recommended this, but if you want to use range-based for loop (yeah, … Read more
The for loop iterates over all the numbers in range(10), that is, [0,1,2,3,4,5,6,7,8,9]. That you change the current value of i has no effect on the next value in the range. You can get the desired behavior with a while loop. i = 0 while i < 10: # do stuff and manipulate `i` as … Read more
for in loops over enumerable property names of an object. for of (new in ES6) does use an object-specific iterator and loops over the values generated by that. In your example, the array iterator does yield all the values in the array (ignoring non-index properties).
You’re modifying the list while you iterate over it. That means that the first time through the loop, i == 1, so 1 is removed from the list. Then the for loop goes to the second item in the list, which is not 2, but 3! Then that’s removed from the list, and then the … Read more