Here is the pure PowerShell way if you are interested. Finding files with at least one Unix line ending (PowerShell v1): dir * -inc *.txt | %{ if (gc $_.FullName -delim “`0” | Select-String “[^`r]`n”) {$_} } Here is how you find and covert Unix line endings to Windows line endings. One important thing to … Read more
If you would like to keep the line breaks, you might try: function parse($text) { // Damn pesky carriage returns… $text = str_replace(“\r\n”, “\n”, $text); $text = str_replace(“\r”, “\n”, $text); // JSON requires new line characters be escaped $text = str_replace(“\n”, “\\n”, $text); return $text; }
The constant PHP_EOL should generally be used for platform-specific output. Mostly for file output really. Actually the file functions already transform \n ←→ \r\n on Windows systems unless used in fopen(…, “wb”) binary mode. For file input you should prefer \n however. While most network protocols (HTTP) are supposed to use \r\n, that’s not guaranteed. … Read more
The correct answer is to use Environment.NewLine, as you’ve noted. It is environment specific and provides clarity over “\r\n” (but in reality makes no difference). foreach (var item in FirmNameList) { if (FirmNames != “”) { FirmNames += “, ” + Environment.NewLine; } FirmNames += item; }
From MSDN: By default, $ matches only the end of the input string. If you specify the RegexOptions.Multiline option, it matches either the newline character (\n) or the end of the input string. It does not, however, match the carriage return/line feed character combination. To successfully match them, use the subexpression \r?$ instead of just … Read more
You can use match on the string containing the line breaks, and the number of elements in that array should correspond to the number of line breaks. enteredText = textareaVariableName.val(); numberOfLineBreaks = (enteredText.match(/\n/g)||[]).length; characterCount = enteredText.length + numberOfLineBreaks; /\n/g is a regular expression meaning ‘look for the character \n (line break), and do it globally … Read more
The lines are probably separated by \r\n in your file. Both \r (carriage return) and \n (linefeed) are considered line-separator characters in Java regexes, and the . metacharacter won’t match either of them. \s will match those characters, so it consumes the \r, but that leaves .* to match the \n, which fails. Your tester … Read more
Use \n as you are using in your string. Set numberOfLines to 0 to allow for any number of lines. label.numberOfLines = 0; Update the label frame to match the size of the text using sizeWithFont:. If you don’t do this your text will be vertically centered or cut off. UILabel *label; // set frame … Read more
Generally you just need to add white-space: pre-line; whitespace trimmed to single whitespace or white-space: pre-wrap; all whitespace preserved to the element’s style (CSS), where you want your text rendered with line-breaks.
Python 3 Solution The print() function accepts an end parameter which defaults to \n (new line). Setting it to an empty string prevents it from issuing a new line at the end of the line. def install_xxx(): print(“Installing XXX… “, end=””, flush=True) install_xxx() print(“[DONE]”) Python 2 Solution Putting a comma on the end of the … Read more