You can make use of differenceWith() with an isEqual() comparator, and invoke isEmpty to check if they are equal or not. var isArrayEqual = function(x, y) { return _(x).differenceWith(y, _.isEqual).isEmpty(); }; var result1 = isArrayEqual( [{a:1, b:2}, {c:3, d:4}], [{b:2, a:1}, {d:4, c:3}] ); var result2 = isArrayEqual( [{a:1, b:2, c: 1}, {c:3, d:4}], [{b:2, … Read more
As lyyons pointed out in the comments, more idiomatic and lodashy way to do this would be to use _.remove, like this _.remove(obj.subTopics, { subTopicId: stToDelete }); Apart from that, you can pass a predicate function whose result will be used to determine if the current element has to be removed or not. _.remove(obj.subTopics, function(currentObject) … Read more
Here is a concrete, working example, using Array.prototype.sort: const arr = [ [500, ‘Foo’], [600, ‘bar’], [700, ‘Baz’] ]; arr.sort((a,b) => a[1].toUpperCase().localeCompare(b[1].toUpperCase())); console.log(arr);
If you don’t wish to use any bundling tools, you will need to provide a path to the lodash folder within node_modules, relative to the JavaScript file that you have the import statement in. If you do not wish to use a bundler, it would also be worthwhile importing from the specific file, the function … Read more
You don’t need lodash for this. The first object is missing your status property and it will be added. SHOWING THREE WAYS HOW YOU CAN DO IT IMMUTABLE VERSION (We create a new array using map) const arrImmutableVersion = arr.map(e => ({…e, status: “active”})); MUTABLE VERSIONS (We change the original array) arr.forEach((el)=>{el.status = “active”;}) or … Read more
Javascript’s object/property system is much more dynamic than most languages, so it’s very easy to add functionality to an object. As functions are first-class objects, they can be added to an object in exactly the same way. Object.assign is the way to add the properties of one object to another object. (Its behaviour is in … Read more
Second highest voted answer doesn’t do proper merge. If second array contains an unique property, it is not taken into account. This approach does a proper merge. Lodash var a = [ { userId:”p1″, item:1}, { userId:”p2″, item:2}, { userId:”p3″, item:4} ]; var b = [ { userId:”p1″, profile:1}, { userId:”p2″, profile:2}, { userId:”p4″, profile:4} … Read more
This is a case of reduction for each unique element. I always use _.groupBy and then _.map the result to an array after applying the reduction. In this case the reduction operation is _.sumBy. var prjMgrValues = [ {“proj_mgr”:”Jack ProjManager”,”submitted_dollars”:12000}, {“proj_mgr”:”Jack ProjManager”,”submitted_dollars”:750000}, {“proj_mgr”:”Joe ProjManager”,”submitted_dollars”:45000} ]; var output = _(prjMgrValues) .groupBy(‘proj_mgr’) .map((objs, key) => ({ ‘proj_mgr’: … Read more
As Palpatim explained, the reason lies in the fact that _.debounce(…) returns a function, which when invoked does its magic. Therefore in your #anonFunction example, you have a key listener, which when invoked does nothing but return a function to the invoker, which does nothing with the return values from the event listener. This is … Read more
If you sort the outer array, you can use _.isEqual() since the inner array is already sorted. var array1 = [[‘a’, ‘b’], [‘b’, ‘c’]]; var array2 = [[‘b’, ‘c’], [‘a’, ‘b’]]; _.isEqual(array1.sort(), array2.sort()); //true Note that .sort() will mutate the arrays. If that’s a problem for you, make a copy first using (for example) .slice() … Read more