ReferenceError: Invalid left-hand side in assignment
You have to use == to compare (or even ===, if you want to compare types). A single = is for assignment. if (one == ‘rock’ && two == ‘rock’) { console.log(‘Tie! Try again!’); }
You have to use == to compare (or even ===, if you want to compare types). A single = is for assignment. if (one == ‘rock’ && two == ‘rock’) { console.log(‘Tie! Try again!’); }
A Float uses a binary (IEEE 754) representation and cannot represent all decimal fractions precisely. For example, let x : Float = 123.456 stores in x the bytes 42f6e979, which is approximately 123.45600128173828. So does x have 3 or 14 fractional digits? You can use NSNumberFormatter if you specify a maximum number of decimal digits … Read more
XSLT is Turing-complete, see for example here or here, hence it can be done. But I have used XSLT only one or two times and can give no solution. UPDATE I just read a tutorial again and found a solution using the following fact. bitset(x, n) returns true, if the n-th bit of x is … Read more
Usage: var results = new[] { 1, 2, 3, 4, 5, 6, 7, 8, 9 }.DifferentCombinations(3); Code: public static class Ex { public static IEnumerable<IEnumerable<T>> DifferentCombinations<T>(this IEnumerable<T> elements, int k) { return k == 0 ? new[] { new T[0] } : elements.SelectMany((e, i) => elements.Skip(i + 1).DifferentCombinations(k – 1).Select(c => (new[] {e}).Concat(c))); } }
As Matt Ball‘s answer explains, or is “and/or”. But or doesn’t work with in the way you use it above. You have to say if “a” in someList or “á” in someList or…. Or better yet, if any(c in someList for c in (“a”, “á”, “à”, “ã”, “â”)): … That’s the answer to your question … Read more
For exactly three terms, you can use this expression: (a ^ b ^ c) && !(a && b && c) The first part is true iff one or three of the terms are true. The second part of the expression ensures that not all three are true. Note that the above expression does NOT generalize … Read more
There’s an answer here using min/max and no branches (https://stackoverflow.com/a/14676309/2233603). Actually 4 min/max operations are enough to find the median, there’s no need for xor’s: median = max(min(a,b), min(max(a,b),c)); Though, it won’t give you the median value’s index… Breakdown of all cases: a b c 1 2 3 max(min(1,2), min(max(1,2),3)) = max(1, min(2,3)) = max(1, … Read more
You could use is() instead of hasClass(): if ($(‘html’).is(‘.m320, .m768’)) { … }
Don’t use “smart keys”. This is a bad idea called “smart keys” or “encoding information in keys”. See this answer which contains this excerpt: Despite it now being easy to implement a Smart Key, it is hard to recommend that you create one of your own that isn’t a natural key, because they tend to … Read more
Let us first get used to a declarative reading of logic programs. Declaratively, a Prolog program states what is true. For example natural_number(0). natural_number(s(X)) :- natural_number(X). The first clause states: 0 is a natural number. The second clause states: If X is a natural number, then s(X) is a natural number. Let us now consider … Read more