What is the meaning of a dot (.) after an integer in c?
It’s same as 0.0, it will treat it as double instead of an integer, so you don’t need to cast it.
It’s same as 0.0, it will treat it as double instead of an integer, so you don’t need to cast it.
Firstly, the expected difference in behaviour is because the operator<<(std::ostream&, const char*) overload (it’s actually a function template specialization, but nevermind for now) has a parameter of type std::ostream& and an lvalue reference can only bind to an lvalue, and in your example the stream is an rvalue so that overload can’t be used. In … Read more
The unary + operator can be used to convert a value to a number in JavaScript. Underscore appears to be testing that the .length property is a number, otherwise it won’t be equal to itself-converted-to-a-number.
Your code, as written, works. You’re probably trying to achieve something unrelated, but similar: std::string c = “hello” + “world”; This doesn’t work because for C++ this seems like you’re trying to add two char pointers. Instead, you need to convert at least one of the char* literals to a std::string. Either you can do … Read more
To be short: firstBigDecimal.compareTo(secondBigDecimal) < 0 // “<” firstBigDecimal.compareTo(secondBigDecimal) > 0 // “>” firstBigDecimal.compareTo(secondBigDecimal) == 0 // “==” firstBigDecimal.compareTo(secondBigDecimal) >= 0 // “>=”
The chosen answer is no longer valid when you try overloads using the == operator in the new version. Now you need to do this: class MyClass { @override bool operator ==(other) { // compare this to other } } But it’s not safe. other is not specified as a type, Something unexpected may happened. … Read more
Firstly, application (whitespace) is the highest precedence “operator”. Secondly, in Haskell, there’s really no distinction between operators and functions, other than that operators are infix by default, while functions aren’t. You can convert functions to infix with backticks 2 `f` x and convert operators to prefix with parens: (+) 2 3 So, your question is … Read more
From the Spec: 6.12.3 InfixOperations An infix operator can be an arbitrary identifier. Infix operators have precedence and associativity defined as follows. … The associativity of an operator is determined by the operator’s last character. Operators ending in a colon ‘:’ are right-associative. All other operators are left- associative. You can always see how these … Read more
The >> operator in your example is used for two different purposes. In C++ terms, this operator is overloaded. In the first example, it is used as a bitwise operator (right shift), 2 << 5 # shift left by 5 bits # 0b10 -> 0b1000000 1000 >> 2 # shift right by 2 bits # … Read more
var c = (a,b); The above uses the comma operator. It evaluates as the value of its right-hand side (i.e. b). var c = a,b; This does not use the comma operator. The comma character here forms part of the var expression which takes a comma-separated list of variables to create in the current scope, … Read more