overloading

Overload resolution with std::function

In C++11… Let’s take a look at the specification of the constructor template of std::function (which takes any Callable): [func.wrap.func.con]/7-10 template<class F> function(F f); template <class F, class A> function(allocator_arg_t, const A& a, F f); 7 Requires: F shall be CopyConstructible. f shall be Callable (20.10.11.2) for argument types ArgTypes and return type R. The … Read more

overloading method priority in java

It is now clear that the method var(int…) is selected and not var(Integer…). The reason is that only certain conversions are allowed to be applied, and it can only be one of these conversions from the list, not a chain of conversions. The java compiler is not allowed to do a widening primitive conversion first, … Read more

How to use Reflection to Invoke an Overloaded Method in .NET

You have to specify which method you want: class SomeType { void Foo(int size, string bar) { } void Foo() { } } SomeType obj = new SomeType(); // call with int and string arguments obj.GetType() .GetMethod(“Foo”, new Type[] { typeof(int), typeof(string) }) .Invoke(obj, new object[] { 42, “Hello” }); // call without arguments obj.GetType() … Read more

Is it possible to narrow the types of overloaded parameters without exhaustively checking each parameter in the function body?

This is now possible to a limited extent with TypeScript 4.6’s Control Flow Analysis for Dependent Parameters. TypeScript can narrow down the types of arguments if the narrowing is done with ===. (A typeof check doesn’t appear to work, at least not yet.) To tweak the example in the question, if the first argument, when … Read more

How do overloaded methods work?

most specific method argument is chosen for overloaded methods In this case, String is subclass of Object. Hence String becomes more specific than Object. Hence Inside String method is printed. Directly from JLS-15.12.2.5 If more than one member method is both accessible and applicable to a method invocation, it is necessary to choose one to … Read more

Java overloading vs overriding

You are basically correct. Overloading is having multiple methods in a single class where the method has the same name. However, the return value is not seen as part of the signature of the method. Thus, you cannot overload a method by changing only the return value. You cannot have the following code, from your … Read more

Overloading functions

In short : No, it is not possible. However, You can mimic this kind of behavior: Obviously, since Matlab is a dynamic language, you can pass arguments of any type and check them. function foo(x) if isnumeric(x) disp(‘ Numeric behavior’); elseif ischar(x) disp(‘ String behavior’); end end You can also use varargin, and check the … Read more

STL algorithms: Why no additional interface for containers (additional to iterator pairs)?

They do introduce ambiguity for many algorithms. A lot of <algorithm> looks like template<class iterator> void do_something(iterator, iterator); template<class iterator, class funct> void do_something(iterator, iterator, funct); If you add additional overloads template<class container, class funct> void do_something(container, funct); the compiler will have some trouble figuring out what do_something(x, y) means. If x and y are … Read more