You are right, the link which you posted in the comment would be probably the best approach. As your question sounded interesting i tried it out. You probably did it also, but here is an snippet (for other, that may come looking) var xmlhttp = new XMLHttpRequest(); xmlhttp.open(“GET”,”data.dat”,false); xmlhttp.setRequestHeader(“Range”, “bytes=100-200”); xmlhttp.send(); console.info(xmlhttp); //–> returns only … Read more
It’s because of UTF-16. Characters outside of the base multilingual plane (BMP) are represented using a surrogate pair in UTF-16 with the first code unit (CU) lies between 0xD800–0xDBFF and the second one between 0xDC00–0xDFFF. Each of the CU represents 10 bits of the code point, allowing total 20 bits of data (0x100000 characters) which … Read more
Range takes, 1, 2, or 3 arguments. This could be implemented with def range(*args), and explicit code to raise an exception when it gets 0 or more than 3 arguments. It couldn’t be implemented with default arguments because you can’t have a non-default after a default, e.g. def range(start=0, stop, step=1). This is essentially because … Read more
Offset function dynamic range makes it possible. Sample data Steps Define a dynamic named range =OFFSET(Sheet1!$A$2,,,1,COUNTA(Sheet1!$A$2:$Z$2)) and give it a name mobileRange Right Click on Chart Click on Select Data This screen will come Click on Edit under Legend Entries.(mobiles is selected) change the Series value to point to mobileRange named range. Now if data … Read more
In case you want the sample to follow a uniform distribution, the problem reduces to generate N random numbers with sum = 1. This, in turn, is a special case of the Dirichlet distribution but can also be computed more easily using the Exponential distribution. Here is how: Take a uniform sample v1 … vN … Read more
You’re modifying the list while you iterate over it. That means that the first time through the loop, i == 1, so 1 is removed from the list. Then the for loop goes to the second item in the list, which is not 2, but 3! Then that’s removed from the list, and then the … Read more
The following should do what you want. In non-IE browsers it turns on designMode, applies a background colour and then switches designMode off again. UPDATE Fixed to work in IE 9. function makeEditableAndHighlight(colour) { sel = window.getSelection(); if (sel.rangeCount && sel.getRangeAt) { range = sel.getRangeAt(0); } document.designMode = “on”; if (range) { sel.removeAllRanges(); sel.addRange(range); } … Read more
The construct of INDEX() >>:<<INDEX() will work when applied to ranges. Not to arrays AFAIK. It will lead to these errors. Maybe try something like: =LET(range,A1:D2,MAKEARRAY(ROWS(range),COLUMNS(range),LAMBDA(r,c,SUM(INDEX(range,r,SEQUENCE(c)))))) This would resemble the construct of your inital formula. However, in the linked question you have mentioned that you’d like to use SCAN() in combination with BYROW(). You have … Read more
Another implementation: shift = 0 while not int(shift) in range(1,27): shift = input(“Please enter your shift (1 – 26) : “)#choose a shift
Rather use regex to test it before sending a 416. Then just parse it by exploding on the comma , and the hyphen -. I also see that you used \d+ in your regex, but those are actually not required. When either of the range indexes is omitted, then it just means “first byte” or … Read more