I’d probably use a regex here: >>> import re >>> s = “The scary ghost ordered an expensive steak” >>> sub_dict = {‘ghost’:’steak’,’steak’:’ghost’} >>> regex = ‘|’.join(sub_dict) >>> re.sub(regex, lambda m: sub_dict[m.group()], s) ‘The scary steak ordered an expensive ghost’ Or, as a function which you can copy/paste: import re def word_replace(replace_dict,s): regex = ‘|’.join(replace_dict) … Read more
It should be: var str=”[{“Company”: “XYZ”,”Description”: “\\”TEST\\””}]”; First, I changed the outer quotes to single quotes, so they won’t conflict with the inner quotes. Then I put backslash before the innermost quotes around TEST, to escape them. And I escaped the backslash so that it will be treated literally. You can get the same result … Read more
A crude (but effective) way of doing it would be to dump the schema into a file, carefully apply the search-and-replace and then re-import. As a matter of fact I did that today 🙂
A generic function: function replace_between($str, $needle_start, $needle_end, $replacement) { $pos = strpos($str, $needle_start); $start = $pos === false ? 0 : $pos + strlen($needle_start); $pos = strpos($str, $needle_end, $start); $end = $pos === false ? strlen($str) : $pos; return substr_replace($str, $replacement, $start, $end – $start); } DEMO
I was able to get it to work but the workflow is poor: control + H to open Find/Replace Select your line of text Click the “Find in selection” icon to the right Alt L or ⎇ ⌘ L on macOS) Enter your find and replace characters in their inputs Click the Replace all icon … Read more
Well, if the string really ends with the pattern, you could do this: str = str.replace(new RegExp(list[i] + ‘$’), ‘finish’);
You need to assign the new value back to the variable. double myDouble = myObject.getDoubleMethod(); // returns 38.1882352941176 System.out.println(myDouble); String myDoubleString = “” + myDouble; System.out.println(myDoubleString); myDoubleString = myDoubleString.replace(“.”, “,”); System.out.println(myDoubleString); myDoubleString = myDoubleString.replace(‘.’, ‘,’); System.out.println(myDoubleString);
It is possible and fairly simple. Django only allows one argument to your filter, but there’s no reason you can’t put all your arguments into a single string using a comma to separate them. So for example, if you want a filter that checks if variable X is in the list [1,2,3,4] you will want … Read more
You are looking for str_replace(). $string = ‘blah blarh bleh bleh blarh’; $result = str_replace( array(‘blah’, ‘blarh’), array(‘bleh’, ‘blerh’), $string ); // Additional tip: And if you are stuck with an associative array like in your example, you can split it up like that: $searchReplaceArray = array( ‘blah’ => ‘bleh’, ‘blarh’ => ‘blerh’ ); $result … Read more
var array = {“from1″:”to1”, “from2″:”to2”} for (var val in array) text = text.replace(new RegExp(val, “g”), array[val]); Edit: As Andy said, you may have to escape the special characters using a script like this one.