The datawrangling blog posted a nice list a while back: http://www.datawrangling.com/some-datasets-available-on-the-web Includes financial, government data (labor, housing, etc.), and too many more to list here.
Follow the crib sheet very, very carefully: https://docs.google.com/document/pub?id=19nQzvKP-CVLd7_VrpwnHfl-AE9fjbJySowONZZtNHzw In particular, I think you need to: Import the actual source for the “google-play-services_lib” project and link it as an Android library. Do this through Project -> Properties -> Android -> Library, Add -> google-play-services_lib (you can right click on your project and choose Properties, then select … Read more
If you know in advance that you’re going to want to multiple samples without overlaps, easiest is to do random.shuffle() on list(range(100)) (Python 3 – can skip the list() in Python 2), then peel off slices as needed. s = list(range(100)) random.shuffle(s) first_sample = s[-10:] del s[-10:] second_sample = s[-10:] del s[-10:] # etc Else … Read more
Yes, you can use dplyr: mtcars %>% group_by(cyl) %>% slice_sample(n = 2)) and the results are like this Source: local data frame [6 x 11] Groups: cyl mpg cyl disp hp drat wt qsec vs am gear carb 1 24.4 4 146.7 62 3.69 3.190 20.00 1 0 4 2 2 26.0 4 120.3 91 … Read more
In versions of dplyr 0.3 and later, this works just fine: df %>% group_by(color) %>% sample_n(size = 3) Old versions of dplyr (version <= 0.2) I set out to answer this using dplyr, assuming that this would work: df %.% group_by(color) %.% sample_n(size = 3) But it turns out that in 0.2 the sample_n.grouped_df S3 … Read more
The following exchange is between Chrome and a static web server, retrieving an MP4 video. Initial request – for the video. Note the Accept-Ranges response header to indicate the server has range header support: GET /BigBuckBunny_320x180.mp4 Cache-Control: max-age=0 Connection: keep-alive Accept-Language: en-GB,en-US,en Host: localhost:8080 Range: Accept: text/html,application/xhtml+xml,application/xml,*/* User-Agent: Mozilla/5.0 (Windows NT 5.1) AppleWebKit/535.7 … Accept-Encoding: … Read more
You are looking to partition the distance from 0 to 1. Choose n – 1 numbers from 0 to 1, sort them and determine the distances between each of them. This will partition the space 0 to 1, which should yield the occasional large result which you aren’t getting. Even so, for large values of … Read more
This is available as the slice_sample function in dplyr: library(dplyr) new_df <- df %>% group_by(ID) %>% slice_sample(n=500) In older versions of R, the function was called sample_n, which has been deprecated.
In the light of the evolving thread, I have updated the below: IE 6 * html .ie6 {property:value;} or .ie6 { _property:value;} IE 7 *+html .ie7 {property:value;} or *:first-child+html .ie7 {property:value;} IE 6 and 7 @media screen\9 { .ie67 {property:value;} } or .ie67 { *property:value;} or .ie67 { #property:value;} IE 6, 7 and 8 @media … Read more
private OutputStream outputStream; private InputStream inStream; private void init() throws IOException { BluetoothAdapter blueAdapter = BluetoothAdapter.getDefaultAdapter(); if (blueAdapter != null) { if (blueAdapter.isEnabled()) { Set<BluetoothDevice> bondedDevices = blueAdapter.getBondedDevices(); if(bondedDevices.size() > 0) { Object[] devices = (Object []) bondedDevices.toArray(); BluetoothDevice device = (BluetoothDevice) devices[position]; ParcelUuid[] uuids = device.getUuids(); BluetoothSocket socket = device.createRfcommSocketToServiceRecord(uuids[0].getUuid()); socket.connect(); outputStream = socket.getOutputStream(); … Read more