The default shell (/bin/sh) under Ubuntu points to dash, not bash. me@pc:~$ readlink -f $(which sh) /bin/dash So if you chmod +x your_script_file.sh and then run it with ./your_script_file.sh, or if you run it with bash your_script_file.sh, it should work fine. Running it with sh your_script_file.sh will not work because the hashbang line will be … Read more
strip only removes characters from the beginning and end of a string. You want to use replace: str2 = str.replace(“\n”, “”) re.sub(‘\s{2,}’, ‘ ‘, str) # To remove more than one space
The third parameter of String.prototype.replace() function was never defined as a standard, so most browsers simply do not implement it. The best way is to use regular expression with g (global) flag. var myStr=”this,is,a,test”; var newStr = myStr.replace(/,/g, ‘-‘); console.log( newStr ); // “this-is-a-test” Still have issues? It is important to note, that regular expressions … Read more
Here are some alternatives. No packages are used in the first 3. 1) reformulate fo <- reformulate(regressors, response = “income”) lm(fo, Duncan) or you may wish to write the last line as this so that the formula that is shown in the output looks nicer: do.call(“lm”, list(fo, quote(Duncan))) in which case the Call: line of … Read more
I suggest you consider passing optional name value to these functions. I say this because it seems like you really want to use the name as a label for something in the end result; so it’s not really the variable itself that matters so much as its name. You could do fun1 <- function (some_variable, … Read more
The reason the re.sub(r'([0-9])’,A[int(r’\g<1>’)],S) does not work is that \g<1> (which is an unambiguous representation of the first backreference otherwise written as \1) backreference only works when used in the string replacement pattern. If you pass it to another method, it will “see” just \g<1> literal string, since the re module won’t have any chance … Read more
A simple possibility (if you’d rather avoid REs) is ‘ ‘.join(mystring.split()) The split and join perform the task you’re explicitly asking about — plus, they also do the extra one that you don’t talk about but is seen in your example, removing trailing spaces;-).
First and foremost, replacement patterns ≠ regular expression patterns We use a regex pattern to search for matches, we use replacement patterns to replace matches found with regex. NOTE: The only special character in a substitution pattern is a backslash, \. Only the backslash must be doubled. Replacement pattern syntax in Python The re.sub docs … Read more
On the replacement side, you must use $1, not \1. And you can only do what you want by making replace an evalable expression that gives the result you want and telling s/// to eval it with the /ee modifier like so: $find=”start (.*) end”; $replace=””foo $1 bar””; $var = “start middle end”; $var =~ … Read more
There are several questions/issues here, so I’ll repeat each section of the poster’s text, block-quoted, and followed by my response. What’s the preferred syntax, and why? Or are they pretty much interchangeable? I would say that the $(some_command) form is preferred over the `some_command` form. The second form, using a pair of backquotes (the “`” … Read more