How do I print unique elements in Perl array?
use List::MoreUtils qw/ uniq /; my @unique = uniq @faculty; foreach ( @unique ) { print $_, “\n”; }
use List::MoreUtils qw/ uniq /; my @unique = uniq @faculty; foreach ( @unique ) { print $_, “\n”; }
You need not to use std::sort. It can be done in a simpler way: if ( std::adjacent_find( myvector.begin(), myvector.end(), std::not_equal_to<>() ) == myvector.end() ) { std::cout << “All elements are equal each other” << std::endl; }
For C/C++: #include <IOKit/IOKitLib.h> void get_platform_uuid(char * buf, int bufSize) { io_registry_entry_t ioRegistryRoot = IORegistryEntryFromPath(kIOMasterPortDefault, “IOService:/”); CFStringRef uuidCf = (CFStringRef) IORegistryEntryCreateCFProperty(ioRegistryRoot, CFSTR(kIOPlatformUUIDKey), kCFAllocatorDefault, 0); IOObjectRelease(ioRegistryRoot); CFStringGetCString(uuidCf, buf, bufSize, kCFStringEncodingMacRoman); CFRelease(uuidCf); }
Use array_key_exists & increment the count, $newArray = array(); foreach ($the_outer_array as $key=>$value) { $firstValue = $value[0]; if ($foundKey = array_key_exists($firstValue,$newArray)) { $newArray[$firstValue] += 1; } else{ $newArray[$firstValue] = 1; } } DEMO.
If you really don’t want to loop, try this: $arr[] = array(‘A’,’B’); $arr[] = array(‘C’,’B’); $arr[] = array(‘C’,’D’); $arr[] = array(‘F’,’A’); $merged = array_unique(call_user_func_array(‘array_merge’, $arr));
Using Data.Map and tuple sections: count = Map.fromListWith (+) . map (, 1) (Add Map.toList if you need a list.)
The issue you’re having between -0. and +0. is part of the specification of how floats are supposed to behave (IEEE754). In some circumstance, one needs this distinction. See, for example, the docs that are linked to in the docs for around. It’s also worth noting that the two zeros should compare to equal, so … Read more
One way would be to convert the arrays to JSON strings, then use a Set to get unique values, and convert back again var arr = [ [1, 1, 2], [1, 2, 1], [1, 1, 2], [1, 2, 1], [2, 1, 1], [2, 1, 1] ]; let set = new Set(arr.map(JSON.stringify)); let arr2 = Array.from(set).map(JSON.parse); … Read more
Your solution: INSERT INTO Words (Word) SELECT @Word WHERE NOT EXISTS (SELECT WordID FROM Words WHERE Word = @Word) …is about as good as it gets. You could simplify it to this: INSERT INTO Words (Word) SELECT @Word WHERE NOT EXISTS (SELECT * FROM Words WHERE Word = @Word) …because EXISTS doesn’t actually need to … Read more