numpy.pad with constant mode does what you need, where we can pass a tuple as second argument to tell how many zeros to pad on each size, a (2, 3) for instance will pad 2 zeros on the left side and 3 zeros on the right side: Given A as: A = np.array([1,2,3,4,5]) np.pad(A, (2, … Read more
I have stumbled upon this problem too and below is what I figured out. When training RNN (LSTM or GRU or vanilla-RNN), it is difficult to batch the variable length sequences. For example: if the length of sequences in a size 8 batch is [4,6,8,5,4,3,7,8], you will pad all the sequences and that will result … Read more
As said in Ben’s answer, colClasses is the easier way to do it. Here is an example: read.table(text=”col1 col2 0012 0001245″, head=T, colClasses=c(‘character’,’numeric’)) col1 col2 1 0012 1245 ## col1 keep 00 but not col2
To pad strings: >>> n = ‘4’ >>> print(n.zfill(3)) 004 To pad numbers: >>> n = 4 >>> print(f'{n:03}’) # Preferred method, python >= 3.6 004 >>> print(‘%03d’ % n) 004 >>> print(format(n, ’03’)) # python >= 2.6 004 >>> print(‘{0:03d}’.format(n)) # python >= 2.6 + python 3 004 >>> print(‘{foo:03d}’.format(foo=n)) # python >= 2.6 … Read more
<?php foreach (range(1, 12) as $month): ?> <option value=”<?= sprintf(“%02d”, $month) ?>”><?= sprintf(“%02d”, $month) ?></option> <?php endforeach?> You’d probably want to save the value of sprintf to a variable to avoid calling it multiple times.
Strings: >>> n = ‘4’ >>> print(n.zfill(3)) 004 And for numbers: >>> n = 4 >>> print(f'{n:03}’) # Preferred method, python >= 3.6 004 >>> print(‘%03d’ % n) 004 >>> print(format(n, ’03’)) # python >= 2.6 004 >>> print(‘{0:03d}’.format(n)) # python >= 2.6 + python 3 004 >>> print(‘{foo:03d}’.format(foo=n)) # python >= 2.6 + python … Read more