If you want a faster solution you can use itertools.repeat
:
from itertools import repeat:
list(zip(repeat(0), range(101)))
benchmark:
%timeit [(0, x) for x in range(101)]
# 3.64 µs ± 19.1 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each)
%timeit list(zip(repeat(0), range(101)))
# 2.81 µs ± 35.3 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each)
Another Pythonic solution:
list((0, x) for x in range(101))