XSLT getting last element

by

You need to put the last() indexing on the nodelist result, rather than as part of the selection criteria. Try:

(//element[@name="D"])[last()]

More Related Contents:

  1. XSLT string replace
  2. how to escape single quote in xslt substring function
  3. Why do indexes in XPath start with 1 and not 0?
  4. XPath find if node exists
  5. How to use starts-with() , contains() and ends-with() in XPath to find the xml node innertext? in XPATH 1.0
  6. How to concat a string to xsl:value-of select=”…?
  7. Display an XML attribute value only on the first encounter with XSL
  8. XSLT with XML source that has a default namespace set to xmlns
  9. Case insensitive XPath contains() possible?
  10. Why does XSLT output all text by default?
  11. how to apply group by on xslt elements
  12. Producing a new line in XSLT
  13. XSLT: How to convert XML Node to String
  14. Check if a string is null or empty in XSLT
  15. XPath with multiple conditions
  16. Using an HTML entity in XSLT (e.g.  )
  17. XSLT: How to change an attribute value during ?
  18. Will XPath 2.0 and/or XSLT 2.0 be implemented in PHP?
  19. Finding the difference between two dateTimes in XSLT
  20. XSLT Replace function not found
  21. How to execute XSLT 2.0 with ant?
  22. XSLT generate UUID
  23. Tokenizing and sorting with XSLT 1.0
  24. What is the difference between ‘or’ and ‘|’ when programming in xslt?
  25. Conver EDT to GMT in XSLT 1.0
  26. Adding element in middle of xml using xslt
  27. WiX Installer: using xslt with heat.exe to update attributes
  28. Inserting a line break in a PDF generated from XSL FO using
  29. Removing empty tags from XML via XSLT
  30. XSLT Bitwise Logic

Leave a Comment