How to determine if a number is binary and has an even amount of zeros with only one regex?
^[1]*(0[1]*0[1]*)*$ which can be interpreted in the following way: find any number of 1 followed by pairs of 00 with optional one or more 1s in between.
^[1]*(0[1]*0[1]*)*$ which can be interpreted in the following way: find any number of 1 followed by pairs of 00 with optional one or more 1s in between.
If you have an integer value, and you want to print it just do the following (in C): int number = 555; printf(“%d”,number); //this prints number in decimal printf(“%x”,number); //this prints number in haxadecimal You must not forget, to a machine, there are only 0’s and 1’s. You just have to define the way you … Read more
A general solution for controlling this distribution is as follows: First generate a uniform random number between 0-100 (or 0-1000 for more control, i.e if you need 60.1% chance for a number) Then if the number is below or equal to 60, assign 1, now you have a 60% chance to assign 1. I hope … Read more