CSS Solution: If you want to apply only CSS base on browser then you can try: @media screen and (-ms-high-contrast: active), (-ms-high-contrast: none) { /* Put your IE-only styles here. Works for IS 10 & IE 11*/ } JavaScript Solution: IE 10 does not support conditional statements. Conditional statements in Internet Explorer 10.. It will … Read more
You get the error because if can only evaluate a logical vector of length 1. Maybe you miss the difference between & (|) and && (||). The shorter version works element-wise and the longer version uses only the first element of each vector, e.g.: c(TRUE, TRUE) & c(TRUE, FALSE) # [1] TRUE FALSE # c(TRUE, … Read more
As part of aiming for portability, there is a very specific set of rules for what a compiler should accept and what it should reject. Those rules both permit and require only a limited form of flow analysis when determining whether a variable is definitely assigned at its use. See the Java Language Specification Chapter … Read more
You can’t do it directly like that… you can do something like this though (not very pretty…): SELECT t.id, t.type, t2.id AS id2, t3.id AS id3 FROM t LEFT JOIN t2 ON t2.id = t.id AND t.type=”t2″ LEFT JOIN t3 ON t3.id = t.id AND t.type=”t3″
It was changed between 3.1 and 3.2: This is a terse description of the new features added to bash-3.2 since the release of bash-3.1. Quoting the string argument to the [[ command’s =~ operator now forces string matching, as with the other pattern-matching operators. So use it without the quotes thus: i=”test” if [[ $i … Read more
>>> import numpy as np >>> a = np.random.randint(0, 5, size=(5, 4)) >>> a array([[4, 2, 1, 1], [3, 0, 1, 2], [2, 0, 1, 1], [4, 0, 2, 3], [0, 0, 0, 2]]) >>> b = a < 3 >>> b array([[False, True, True, True], [False, True, True, True], [ True, True, True, True], … Read more
The bug is probably somewhere else in your code, because it should work fine: >>> 3 not in [2, 3, 4] False >>> 3 not in [4, 5, 6] True Or with tuples: >>> (2, 3) not in [(2, 3), (5, 6), (9, 1)] False >>> (2, 3) not in [(2, 7), (7, 3), “hi”] … Read more
one way to do this would be to use indexing with .loc. Example In the absence of an example dataframe, I’ll make one up here: import numpy as np import pandas as pd df = pd.DataFrame({‘c1’: list(‘abcdefg’)}) df.loc[5, ‘c1’] = ‘Value’ >>> df c1 0 a 1 b 2 c 3 d 4 e 5 … Read more
I don’t think there is a way to do variable length string comparisons completely in preprocessor directives. You could perhaps do the following though: #define USER_JACK 1 #define USER_QUEEN 2 #define USER USER_JACK #if USER == USER_JACK #define USER_VS USER_QUEEN #elif USER == USER_QUEEN #define USER_VS USER_JACK #endif Or you could refactor the code a … Read more
To formalize some of the approaches laid out above: Create a function that operates on the rows of your dataframe like so: def f(row): if row[‘A’] == row[‘B’]: val = 0 elif row[‘A’] > row[‘B’]: val = 1 else: val = -1 return val Then apply it to your dataframe passing in the axis=1 option: … Read more