To get the item from the ListView item selected refer to ContextMenuInfo object (see last implemented method below). Full solution as follows: 1) register ListView for context menu in ListActivity class @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); // … getListView().setAdapter(mAdapter); registerForContextMenu(getListView()); } 1a) if you have complex View on your list you might need … Read more
In the registration editor (regedit.exe) find: Context menu for right click on folders in left panel of Windows Explorer or on background of a directory in right panel: HKEY_CLASSES_ROOT\Directory\Background\shell if you are administrator HKEY_CURRENT_USER\Software\Classes\directory\Background\shell if you are a normal user Context menu for right click on folders in right panel of Windows Explorer: HKEY_CLASSES_ROOT\Directory\shell if … Read more
You can use the CellMouseEnter and CellMouseLeave to track the row number that the mouse is currently hovering over. Then use a ContextMenu object to display you popup menu, customised for the current row. Here’s a quick and dirty example of what I mean… private void dataGridView1_MouseClick(object sender, MouseEventArgs e) { if (e.Button == MouseButtons.Right) … Read more
I found a much simpler solution. In the code behind for the UserControl: NameScope.SetNameScope(contextMenu, NameScope.GetNameScope(this));
Identify the file type (ProgID) for .jpg files This can be done by checking the default value of HKEY_CLASSES_ROOT\.jpg. It could be anything based on what you’ve installed, but for the purposes of this example, we’ll call it jpegfile, a common default. Set the context menu item (verb) properties for that file type You can … Read more
I know this question is very old, but just came up with the same problem and solved it myself, so I’m answering in case anyone finds this through google as I did. I based my solution on @Andrew’s one, but basically modified everything afterwards. EDIT: seeing how popular this has been lately, I decided to … Read more
Answering your question – use contextmenu event, like below: if (document.addEventListener) { document.addEventListener(‘contextmenu’, function(e) { alert(“You’ve tried to open context menu”); //here you draw your own menu e.preventDefault(); }, false); } else { document.attachEvent(‘oncontextmenu’, function() { alert(“You’ve tried to open context menu”); window.event.returnValue = false; }); } <body> Lorem ipsum… </body> But you should ask … Read more
Please read about minimal examples. Without reading your code, I believe you have run into a well known issue addressed in previous questions and answers that needs 2 lines to illustrate. Names in function bodies are evaluated when the function is executed. funcs = [lambda: i for i in range(3)] for f in funcs: print(f()) … Read more