On Python ≥ 3.5, use pathlib.Path.mkdir: from pathlib import Path Path(“/my/directory”).mkdir(parents=True, exist_ok=True) For older versions of Python, I see two answers with good qualities, each with a small flaw, so I will give my take on it: Try os.path.exists, and consider os.makedirs for the creation. import os if not os.path.exists(directory): os.makedirs(directory) As noted in comments … Read more
In standard C (using setjmp/longjmp) and C++ (using exceptions), it is possible to effectively return to marked points closer to the root of the CFG. In effect, a function may never return, but if it does return, it will be to the point following the call. However, the low-level nature of the setjmp mechanism actually … Read more
throw new RuntimeException(); or String exceptionMsg = “Error”; throw new RuntimeException(exceptionMsg); — public class X { public X() { Y.CreateException(); //or Y.CreateException(“Error”); } } public class Y { public static void createException() { throw new RuntimeException(); } public static void createException(String msg) { throw new RuntimeException(msg); } }
First of all, and that’s supposed to solve the problem. If you use an ArrayList you should check its documentation. When you supposed to go through a simple array you use “nameOfArray.length”, right? Well, the ArrayList has the method “.size()” which bascialy has the same use. So your loop would be better this way : … Read more
Obviously enough the executable file provided as the FileName does not exist on disk. You might want to check for its existence before trying to execute it.
You should read new inputs inside your loop: try { … while (true) { num = Integer.parseInt(data); myArray.add(num); } } catch (NumberFormatException e) { }; Currently you are adding the same input infinite times to your List. P.S. perhaps you shouldn’t use an infinite while loop. How do you plan to finish reading the inputs? … Read more
i need to throw an exception.Can i use try catch The try/catch block is for catching an exception and do something with that information. If you need to throw an exception, simply throw it if (fileEntries.Length == 0) { throw new Exception(“No *.csv files available”); } this exception will now be thrown upwards to the … Read more
You have a problem in your Median() method. Try changing if (count % 2 == 0){ median = (scores[scores.length/2-1] + scores[scores.length/2])/2; } else { median = scores[scores.length/2]; } to if (count % 2 == 0) median = (scores[count/2] + scores[count/2 – 1])/2; else median = scores[count/2]; Because you have a fixed-size array with 500 elements, … Read more
Assuming you have enough memory: try { std::vector<std::vector<double>> vec(5000000, std::vector<double>(5000000)); // … } catch (std::bad_alloc const& e) { // … }
There are two problems. First, your printf is expecting 4 arguments, but you are supplying only one. Second, %d says you are expecting the argument to be a number, but you are providing a String. System.out.printf(“%d%n%d%n%d%n%d%n”, 1, 2, 3, 4);