You will get ” Unexpected anonymous System.register call” because the references are not being loaded in the correct order. I use JSPM to properly build my angular app for production. There are 4 parts to the process. Part 1: Compile your typescript files var ts = require(“gulp-typescript”); var tsProject = ts.createProject(“./App/tsconfig.json”); gulp.task(“compile:ts”, function () { … Read more
It’s a feature programs cannot stay without. You can try yargs. npm install –save-dev yargs You can use it like this: gulp mytask –production –test 1234 In the code, for example: var argv = require(‘yargs’).argv; var isProduction = (argv.production === undefined) ? false : true; For your understanding: > gulp watch console.log(argv.production === undefined); <– … Read more
The code require(‘./locale/’ + name) can use every file in the locale dir. So webpack includes every file as module in your bundle. It cannot know which language you are using. There are two plugins that are useful to give webpack more information about which module should be included in your bundle: ContextReplacementPlugin and IgnorePlugin. … Read more
Gulp doesn’t offer any kind of util for that, but you can use one of the many command args parsers. I like yargs. Should be: var argv = require(‘yargs’).argv; gulp.task(‘my-task’, function() { return gulp.src(argv.a == 1 ? options.SCSS_SOURCE : options.OTHER_SOURCE) .pipe(sass({style:’nested’})) .pipe(autoprefixer(‘last 10 version’)) .pipe(concat(‘style.css’)) .pipe(gulp.dest(options.SCSS_DEST)); }); You can also combine it with gulp-if to … Read more
When installing a tool globally it’s to be used by a user as a command line utility anywhere, including outside of node projects. Global installs for a node project are bad because they make deployment more difficult. npm 5.2+ The npx utility bundled with npm 5.2 solves this problem. With it you can invoke locally … Read more
You forgot to install the gulp-cli package: npm install -g gulp-cli Then you can run the command “gulp” from the command line.
Quick answer On src, you can always specify files to ignore using “!”. Example (you want to exclude all *.min.js files on your js folder and subfolder: gulp.src([‘js/**/*.js’, ‘!js/**/*.min.js’]) You can do it as well for individual files. Expanded answer: Extracted from gulp documentation: gulp.src(globs[, options]) Emits files matching provided glob or an array of … Read more
I hit the same error. I suspect you’re using Node.js 12 and Gulp.js 3. That combination does not work: Gulp.js 3 is broken on Node.js 12 #2324 A previous workaround from Jan. does not work either: After update to Node.js 11.0.0 running Gulp.js exits with ‘ReferenceError: internalBinding is not defined’ #2246 Solution: Either upgrade to … Read more
Since your task might contain asynchronous code you have to signal gulp when your task has finished executing (= “async completion”). In Gulp 3.x you could get away without doing this. If you didn’t explicitly signal async completion gulp would just assume that your task is synchronous and that it is finished as soon as … Read more
By default, gulp runs tasks simultaneously, unless they have explicit dependencies. This isn’t very useful for tasks like clean, where you don’t want to depend, but you need them to run before everything else. I wrote the run-sequence plugin specifically to fix this issue with gulp. After you install it, use it like this: var … Read more