How to convert a byte array to a hex string in Java?
How to convert a byte array to a hex string in Java?
How to convert a byte array to a hex string in Java?
Update (2021) – Java 17 now includes java.util.HexFormat (only took 25 years): HexFormat.of().parseHex(s) For older versions of Java: Here’s a solution that I think is better than any posted so far: /* s must be an even-length string. */ public static byte[] hexStringToByteArray(String s) { int len = s.length(); byte[] data = new byte[len / … Read more
How do you convert a byte array to a hexadecimal string, and vice versa?
It depends on what the target is for your application. If this is being loaded onto a microprocessor, which is why I am assuming you need a hex file, you will need to download the compiler for the microprocessor. This can probably be obtained on the chip manufacturer website. Once you acquire this you will … Read more
#define SECRET { 0x0b, 0x0b, 0x0b, 0x0b, 0x0b, 0x0b, 0x0b, 0x0b , 0x0b , 0x0b , 0x0b , 0x0b , 0x0b , 0x0b , 0x0b , 0x0b} unsigned char* key = SECRET; is not correct. You can use: #define SECRET { 0x0b, 0x0b, 0x0b, 0x0b, 0x0b, 0x0b, 0x0b, 0x0b , 0x0b , 0x0b , 0x0b … Read more
That’s a string of 32 characters, being hexadecimal digits. That makes 16 bytes, or 128 bits. m0skit0 told you how to store it in a string. If you actually want to store that in an integer, you’d need something like unsigned long long intvar = strtoull( stringvar, NULL, 16 ) – provided “long long” on … Read more
There are 16 choices for each of the 3 digits, so: 16*16*16 = 4096
If you have an integer value, and you want to print it just do the following (in C): int number = 555; printf(“%d”,number); //this prints number in decimal printf(“%x”,number); //this prints number in haxadecimal You must not forget, to a machine, there are only 0’s and 1’s. You just have to define the way you … Read more