The problem C++ includes useful generic functions like std::for_each and std::transform, which can be very handy. Unfortunately they can also be quite cumbersome to use, particularly if the functor you would like to apply is unique to the particular function. #include <algorithm> #include <vector> namespace { struct f { void operator()(int) { // do something … Read more
Try this code: a = input(“enter first number\n”) b= input(“enter second number\n”) limit=[] limit.append(a) limit.append(b) natNo=range(1,1000) xyz = [] for i in limit: xyz +=filter(lambda x: x == i or x % i==0, natNo) set = {} map(set.__setitem__, xyz, []) nums=set.keys() print “the multiples of the given numbers are: “+str(nums) c=reduce(lambda x, y:x+y, nums) print … Read more
You could implement it like this: def switcher(cases, default_func=None): def switch(value): for case_func, result in cases: if case_func(value): return result(value) if default_func is not None: return default_func(value) else: raise RuntimeError(“No case matched and no default given”) return switch Usable as my_switch = switcher([ (lambda value: value == nBins, maxBucket), (lambda value: value < nBins, defaultBucket), … Read more
Does the String in Map<String, List<A>> related to the output? I assume that you want to get every pair <F, E> from the original map right? So this might help Map<String, List<A>> input; input.values().stream() .flatMap(Collection::stream) .map(a -> a.getListB()) // extract list B from A .flatMap(Collection::stream) // Here you get all B instances .collect( toMap( b … Read more
In C++20 and later auto lambda20 = []<class F, class…Ts>(F &&fn, Ts &&…args) { return std::forward<F>(fn)(std::forward<Ts>(args)…); }; In C++pre20 : C++11,14,17 auto lambda14 = [](auto &&fn, auto &&…args) { return std::forward< std::conditional_t< std::is_rvalue_reference_v<decltype(fn)>, typename std::remove_reference_t<decltype(fn)>, decltype(fn)> >(fn)( std::forward< std::conditional_t<std::is_rvalue_reference<decltype(args)>::value, typename std::remove_reference<decltype(args)>::type, decltype(args) >>(args)…); }; Example #include <iostream> using namespace std; int main() { auto lambda20 … Read more
int(x) yields your error, since you can not convert “A” into an integer Correct would be: a=”ABCD” b=map(lambda x:x,a) print(list(b)) As mentioned in the comments, the following gives the same result: print(list(a)) You should probably check out some more lambda tutorials first: http://www.secnetix.de/olli/Python/lambda_functions.hawk
You are using FirstOrDefault so you are returning only the first. PromotionList dataPromotion = authenticateCustomerResponseRootObject.Response.AuthenticateCustomerResponse.EligiblePromotions.PromotionList.Where(p => p.LineOfBusiness.ToUpper().Equals(“Data”)).FirstOrDefault(); If you want all of them just remove that call at the end and replace with a ToList, ToArray or similar that meets your needs: var data = authenticateCustomerResponseRootObject.Response.AuthenticateCustomerResponse.EligiblePromotions.PromotionList.Where(p => p.LineOfBusiness.ToUpper().Equals(“Data”)).ToList(); Also as mentioned in the comments your … Read more
Since you have a List<object> that actually contains List<List<Player>> and you want to get a list of players in one big list. Unfortunately for some external reason you are unable to change the API to give you sensibly typed data, you need to go through a couple of hoops. So given this: List<object> players = … Read more
Resolved. The method was called recursively, creating the parameter and the expression and returned to himself. In this process the parameters were removed from memory, as they had already been used believed not to have problems. But they need to be kept in memory until the time of compilation. In this case I used a … Read more
AND. But you can use AND var test = db.table.Where(x=>x.id == x && x.name == name).ToList(); OR var test = db.table.Where(x=>x.id == x || x.name == name).ToList();