Two approaches you can use here. Approach 1: y = [1; 3; 2; 1; 3]; yvec = zeros(numel(y),3); yvec(sub2ind(size(yvec),1:numel(y),y’))=1 Approach 2 (One-liner): yvec = bsxfun(@eq, 1:3,y)
If you don’t have access to findpeaks, the basic premise behind how it works is that for each point in your signal, it searches a three element window that is centred at this point and checks to see whether the centre of this window is larger than the left and right element of this window. … Read more
Plotting a function of two variables would normally mean a 3-dimensional plot – in MATLAB you would use the function plot3 for that. To plot your function f(x,y) in the interval [-10,10] for both X and Y, you could use the following commands: x = [-10:.1:10]; y = [-10:.1:10]; plot3(x, y, x.^2 + 3*y) grid … Read more
The function you’re looking for is repmat(). v10 = repmat(v, 1, 5)
Well, I know that the poster explicitly asked for a for loop, and Jeff Mather’s answer provided exactly that. But still I got curious whether it is possible to decompose a matrix into tiles (sub-matrices) of a given size without a loop. In case someone else is curious, too, here’s what I have come up … Read more
If you stumble upon this error message and don’t know what it means. Take comfort in this: 90% of us have googled the same phrase. “Undefined function ‘int’ for input arguments of type ‘double’.” The error message is pretty self-explanatory, but may still cause confusion. (I chose ‘int’ at random, it could just as well … Read more
In the line for col=1:1:n, col can get up to the value n, even when row is still 1. Therefore when you call factorial(row-col), row can be 1 and col can be 2. This is where it can be negative.