Thankyou Frank.i got the idea. Here is the working code. Option Explicit Private Sub CommandButton1_Click() Dim directory As String, fileName As String, sheet As Worksheet, total As Integer Dim fd As Office.FileDialog Set fd = Application.FileDialog(msoFileDialogFilePicker) With fd .AllowMultiSelect = False .Title = “Please select the file.” .Filters.Clear .Filters.Add “Excel 2003”, “*.xls?” If .Show = … Read more
Something like that should be what you need private void button1_Click(object sender, RoutedEventArgs e) { // Create OpenFileDialog Microsoft.Win32.OpenFileDialog dlg = new Microsoft.Win32.OpenFileDialog(); // Set filter for file extension and default file extension dlg.DefaultExt = “.png”; dlg.Filter = “JPEG Files (*.jpeg)|*.jpeg|PNG Files (*.png)|*.png|JPG Files (*.jpg)|*.jpg|GIF Files (*.gif)|*.gif”; // Display OpenFileDialog by calling ShowDialog method Nullable<bool> … Read more
Long story short: The solution is to show user interactions from a class, that is part of the view component. This means, such a class must be a class that is unknown to the view model and therefore can’t be invoked by the view model. The solution of course can involve code-behind implementations as code-behind … Read more
Basically you need the FolderBrowserDialog class: Prompts the user to select a folder. This class cannot be inherited. Example: using(var fbd = new FolderBrowserDialog()) { DialogResult result = fbd.ShowDialog(); if (result == DialogResult.OK && !string.IsNullOrWhiteSpace(fbd.SelectedPath)) { string[] files = Directory.GetFiles(fbd.SelectedPath); System.Windows.Forms.MessageBox.Show(“Files found: ” + files.Length.ToString(), “Message”); } } If you work in WPF you have … Read more
I have a dialog that I wrote called an OpenFileOrFolder dialog that allows you to open either a folder or a file. If you set its AcceptFiles value to false, then it operates in only accept folder mode. You can download the source from GitHub here
Tkinter is the easiest way if you don’t want to have any other dependencies. To show only the dialog without any other GUI elements, you have to hide the root window using the withdraw method: import tkinter as tk from tkinter import filedialog root = tk.Tk() root.withdraw() file_path = filedialog.askopenfilename() Python 2 variant: import Tkinter, … Read more
The API for showOpenDialog() refers to showDialog(), which says, “If the parent is null, then the dialog depends on no visible window, and it’s placed in a look-and-feel-dependent position such as the center of the screen.” The example below positions the chooser in the center of the screen on my L&F. You might see how … Read more
Try something like this var openDialog = new OpenFileDialog(); if (openDialog.ShowDialog == DialogResult.OK) { using (var stream = File.OpenRead(openDialog.FileName) { //read everything here } }
You need to use the DialogResult to get the event of open confirmation by the user. Then you can use a stream to read the file. Here is some sample code (provided by MS in the MSDN – source:https://msdn.microsoft.com/en-us/library/system.windows.forms.openfiledialog(v=vs.110).aspx): private void button1_Click(object sender, System.EventArgs e) { Stream myStream = null; OpenFileDialog openFileDialog1 = new OpenFileDialog(); … Read more