In case it was still unclear on how to perform the task here’s an implementation using basic Python with open(‘file.csv’, ‘r’) as in_file, open(‘result.csv’, ‘w’) as out_file: # Open input and output files out_file.write(next(in_file)) # Reads header from input file and writes to output file for line in in_file: # For each line in file … Read more
Some info on enumerate by typing help(enumerate) enumerate(iterable[, start]) -> iterator for index, value of iterable Return an enumerate object. iterable must be another object that supports iteration. The enumerate object yields pairs containing a count (from start, which defaults to zero) and a value yielded by the iterable argument. enumerate is useful for obtaining … Read more
This is the reason a try/catch block is often ill-advised. Your error was not that the file could not be opened, but instead that this line was throwing an error: f.write(student + “\n”) + does not append a dictionary (student) and a string (\n). Your try/catch block is reporting this as an open file error.
When using combinations() you are getting all pairs, even the non-adjacent ones. You can create a function that will return the adjacent pairs. I’ve tried the following code and it worked, maybe it can give you some insight: import os import re from collections import Counter def pairs(text): ans = re.findall(r'[A-Za-z]+’, text) return (tuple(ans[i:i+2]) for … Read more
b and c are different instances of class A. And a.append is a method used to append value to list.
Couple of points: Misplaced return statement. Should be at end. if yes(): It is wrong. You want to compare function input with yes. It should be if s == ‘yes’:. Same for rest also. Since you have written function definition as def shut_down(s):, it is expecting one argument. You should pass one argument while calling … Read more
From https://docs.python.org/2/tutorial/classes.html : The simplest form of class definition looks like this: class ClassName: <statement-1> . . . <statement-N>
The way to do this is clearly documented here. Example: >>> myString = “subString1|substring2|subString3” >>> myString = myString.split(“|”) >>> print myString [“subString1”, “subString2”, “subString3”]
You can use a generator expression within the sum function >>> sum(i**i for i in range(1,11)) 10405071317