I advise you to go with Scanner instead of DataInputStream. Scanner is specifically designed for this purpose and introduced in Java 5. See the following links to know how to use Scanner. Java Documentation Java Tutorial Example Scanner s = new Scanner(System.in); System.out.println(s.nextInt()); System.out.println(s.nextInt()); System.out.println(s.next()); System.out.println(s.next());
As someone already wrote in a comment, you don’t have to use the cat before readline(). Simply write: readline(prompt=”Press [enter] to continue”) If you don’t want to assign it to a variable and don’t want a return printed in the console, wrap the readline() in an invisible(): invisible(readline(prompt=”Press [enter] to continue”))
As @Ron Reiter pointed out, you can’t use readline() because cout doesn’t print newlines implicitly — you either need std::endl or “\n” here. For an interactive use, when you can’t change the child program, pexpect module provides several convenience methods (and in general it solves for free: input/output directly from/to terminal (outside of stdin/stdout) and … Read more
is there any performance difference related to these methods? YES there is a difference File.ReadAllLines() method reads the whole file at a time and returns the string[] array, so it takes time while working with large size of files and not recommended as user has to wait untill the whole array is returned. File.ReadLines() returns … Read more
You should add “throws IOException” to your main method: public static void main(String[] args) throws IOException { You can read a bit more about checked exceptions (which are specific to Java) in JLS.
This should do what you want (file contents in a list, by line, without \n) with open(filename) as f: mylist = f.read().splitlines()
you can code like: $val=”Veg Tomato Potato Fruits mango banana”; $textAreaVal = $val; $arrVal = explode(PHP_EOL, $textAreaVal); for($i=0; $i < count($arrVal); $i++){ $type=””; $isInIf = false; if($arrVal[i] == ‘Veg’){ $type=”Veg”; }else if($arrVal[i] == ‘Fruits’){ $type=”Fruits”; } if($type != ”){ // your insert query here // insert into tbl(type, name) values(‘$type’, ‘$arrVal[i]’) } }