Is it possible to change the return value of a method in this case? [closed]
assert is a checking instruction, not a assignment one. You can’t get a new value from getValue() without using a member variable.
assert is a checking instruction, not a assignment one. You can’t get a new value from getValue() without using a member variable.
The function fun() is returning an int, you are just not assigning it to anything. So the return value is being discarded as it is not assigned to anything. printf by the way, is not a void function but returns the number of characters printed, which is 5 in case of “Hello”.
You can return an object. var Get_Event_Id = function() { return { EventId: 3, EndTime: ‘2014-04-24T11:00:00’ } }; var test = Get_Event_Id(); console.log(test.EventId); http://jsfiddle.net/8LcYr/
You can add in a function parameter that allows you to print out within the function or not: def GetNumber(print_num=False): number = 45 if print_num: print(number) return number GetNumber(True) num = GetNumber() print(“my num is: {}\n”.format(num)); GetNumber(True) will print out the number from within the function, whereas GetNumber() will simply return the number without printing … Read more
No. The compiler is allowed to elide the call to the copy constructor in some cases. Look up RVO (Return Value Optimization) and NRVO (Named Return Value Optimization). Also, since C++17, this optimization is guaranteed in some cases. Additionally, if the returned type is movable, the compiler may do a move rather than a copy … Read more