You can use the SimpleDateFormat class for formatting date in your desired format. Just check this link where you get an idea for your example. For example: String dateStr = “04/05/2010”; SimpleDateFormat curFormater = new SimpleDateFormat(“dd/MM/yyyy”); Date dateObj = curFormater.parse(dateStr); SimpleDateFormat postFormater = new SimpleDateFormat(“MMMM dd, yyyy”); String newDateStr = postFormater.format(dateObj); Update: The detailed example … Read more
This works public class Timeis { public static void main(String s[]) { long ts = 1022895271767L; SimpleDateFormat sdf = new SimpleDateFormat(” MMM d ‘at’ hh:mm a”); // CREATE DateFormatSymbols WITH ALL SYMBOLS FROM (DEFAULT) Locale DateFormatSymbols symbols = new DateFormatSymbols(Locale.getDefault()); // OVERRIDE SOME symbols WHILE RETAINING OTHERS symbols.setAmPmStrings(new String[] { “am”, “pm” }); sdf.setDateFormatSymbols(symbols); String … Read more
Date and time formats are well described below SimpleDateFormat (Java Platform SE 7) – Date and Time Patterns There could be n Number of formats you can possibly make. ex – dd/MM/yyyy or YYYY-‘W’ww-u or you can mix and match the letters to achieve your required pattern. Pattern letters are as follow. G – Era … Read more
You are using the format pattern string yyyyMMdd. You are parsing the date-time string 2018-06-20 00:00:00. 2018 matches yyyy. MM means that month should be two chars, so -0 is taken for the month. And -0 or just 0 is taken to be the month before month 1 of 2018, that is, December 2017. Finally … Read more
Seems that you can use this: import java.util.Calendar; import javax.xml.bind.DatatypeConverter; public class TestISO8601 { public static void main(String[] args) { parse(“2012-10-01T19:30:00+02:00”); // UTC+2 parse(“2012-10-01T19:30:00Z”); // UTC parse(“2012-10-01T19:30:00”); // Local } public static Date parse(final String str) { Calendar c = DatatypeConverter.parseDateTime(str); System.out.println(str + “\t” + (c.getTime().getTime()/1000)); return c.getTime(); } }
You should use HH:mm. hh ranges 01-12, while HH ranges 1-23. Update Check the doc of SimpleDateFormat: H: Hour in day (0-23) h: Hour in am/pm (1-12)
tl;dr i need to make a Date Object from String input but the time zone should remain UTC. LocalDate.parse( “23.01.2017” , DateTimeFormatter.ofPattern( “dd.MM.uuuu” ) ) …and… LocalTime.parse( “12:34:56” ) …combine… OffsetDateTime.of( datePart , timePart , ZoneOffset.UTC ) Details You are using troublesome confusing old date-time classes that are now supplanted by the java.time classes. OffsetDateTime … Read more
Use this. java.util.Date date = new Date(“Sat Dec 01 00:00:00 GMT 2012”); SimpleDateFormat formatter = new SimpleDateFormat(“yyyy-MM-dd”); String format = formatter.format(date); System.out.println(format); you will get the output as 2012-12-01
I also recommend using Joda as mentioned before. Solving your problem using standard Java Date objects only can be done as follows: // **** YOUR CODE **** BEGIN **** long ts = System.currentTimeMillis(); Date localTime = new Date(ts); String format = “yyyy/MM/dd HH:mm:ss”; SimpleDateFormat sdf = new SimpleDateFormat(format); // Convert Local Time to UTC (Works … Read more
The JavaDoc on parse(…) states the following: parsing does not necessarily use all characters up to the end of the string It seems like you can’t make SimpleDateFormat throw an exception, but you can do the following: SimpleDateFormat sdf = new SimpleDateFormat(“yyyy/MM/d”); sdf.setLenient(false); ParsePosition p = new ParsePosition( 0 ); String t1 = “2011/12/12aaa”; System.out.println(sdf.parse(t1,p)); … Read more