1 The keyword static is a keyword and does not need to be added when trying to call a function marked with static. See this for more information. 2 You also cannot implicitily convert a structure to another data-type. You are trying to do this in the print_abc function. You need to explicitly access the … Read more
It is always a good habit to set the pointer to NULL after freeing it. Since the memory you are accessing is still intact you are seeing right values for l->val. Node *l=malloc(sizeof(Node)); l->key=”foo”; l->val=”bar”; free(l); l = NULL;
assuming void foo(const char*) call foo(zombies[42].m_dna);
Valgrind says that the illegal write is occurring at Address 0x6172676f72502074. If you look at that address as ASCII characters, it’s: argorP t, or converting from little endian: t Progra. This looks like part of one of your menu items, “9. Abort Program”. Maybe the bug is that menu_init() is writing past the end of … Read more
Silly mistakes are there. Use below code compiles in VS2013 #include <vector> struct A : public std ::vector<A> { A(); virtual ~A(); };
Your Test structure is quite large, 588,000 bytes, which might be too large for automatic storage. Make it static should solve the problem, but will make your code non reentrant and definitely not thread safe. If the problem is with the maximum packet size, you must break the transmission into smaller packets. Use a smaller … Read more
The -> operator is only syntactical sugar: x->y is the same as (*x).y The parentheses are necessary due to the . operator having higher precedence than the * operator.
<< is the left shift operator. You can better visualize it in binary: 1 0000 0001 << 1 ^ shift this one bit to the left —- = ——— 2 0000 0010 1 0000 0001 << 2 ^ shift this two bits to the left —- = ——— 4 0000 0100 3 0000 0011 << … Read more