First make sure that the input element is visible As stated by Mark Collin in the discussion here: Don’t click on the browse button, it will trigger an OS level dialogue box and effectively stop your test dead. Instead you can use: driver.findElement(By.id(“myUploadElement”)).sendKeys(“<absolutePathToMyFile>”); myUploadElement is the id of that element (button in this case) and … Read more
This is because images and tmp_file_upload are only writable by root user. For upload to work we need to make the owner of those folders same as httpd process owner OR make them globally writable (bad practice). Check apache process owner: $ps aux | grep httpd. The first column will be the owner typically it … Read more
Use: if (function_exists(‘curl_file_create’)) { // php 5.5+ $cFile = curl_file_create($file_name_with_full_path); } else { // $cFile=”@” . realpath($file_name_with_full_path); } $post = array(‘extra_info’ => ‘123456’,’file_contents’=> $cFile); $ch = curl_init(); curl_setopt($ch, CURLOPT_URL,$target_url); curl_setopt($ch, CURLOPT_POST,1); curl_setopt($ch, CURLOPT_POSTFIELDS, $post); $result=curl_exec ($ch); curl_close ($ch); You can also refer: http://blog.derakkilgo.com/2009/06/07/send-a-file-via-post-with-curl-and-php/ Important hint for PHP 5.5+: Now we should use https://wiki.php.net/rfc/curl-file-upload but if … Read more
my result looks like this: public static async Task<string> Upload(byte[] image) { using (var client = new HttpClient()) { using (var content = new MultipartFormDataContent(“Upload—-” + DateTime.Now.ToString(CultureInfo.InvariantCulture))) { content.Add(new StreamContent(new MemoryStream(image)), “bilddatei”, “upload.jpg”); using ( var message = await client.PostAsync(“http://www.directupload.net/index.php?mode=upload”, content)) { var input = await message.Content.ReadAsStringAsync(); return !string.IsNullOrWhiteSpace(input) ? Regex.Match(input, @”http://\w*\.directupload\.net/images/\d*/\w*\.[a-z]{3}”).Value : null; } … Read more
Phew, Django documentation really does not have good example about this. I spent over 2 hours to dig up all the pieces to understand how this works. With that knowledge I implemented a project that makes possible to upload files and show them as list. To download source for the project, visit https://github.com/axelpale/minimal-django-file-upload-example or clone … Read more
You need a script that runs on the server to move the file to the uploads directory. The jQuery ajax method (running on the client in the browser) sends the form data to the server, then a script running on the server handles the upload. Your HTML is fine, but update your JS jQuery script … Read more
Took the code above and fixed because it throws Internal Server Error 500. There are some problems with \r\n badly positioned and spaces etc. Applied the refactoring with memory stream, writing directly to the request stream. Here is the result: public static void HttpUploadFile(string url, string file, string paramName, string contentType, NameValueCollection nvc) { log.Debug(string.Format(“Uploading … Read more