I found an open source project for implementing what I was trying. It processes the video with metadata through an IP camera. Although it does not send video directly to a phone, it does broadcast video for various devices to watch. The source code can be found at the following project page http://code.google.com/p/ipcamera-for-android/. With Android … Read more
this works for me (using opencv 2.4.9): vcap = cv.VideoCapture(“rtsp://192.168.1.2:8080/out.h264”) while(1): ret, frame = vcap.read() cv.imshow(‘VIDEO’, frame) cv.waitKey(1)
I’ve spent several hours trying to hack the original VideoView source code and Now I can confirm VideoView can be hacked to behavior what you want – retain buffering after surface destroyed. I’ve tested on my Samsung Galaxy S2, which works as expected, in my case, the video buffering (streaming m4v video from remote http … Read more
You don’t need MP4Box to generate the required output, but you’ll need to chunk the content yourself looking for boxes in the generated file. Basically you’ll generate an fMP4 with H264, and send to the browser the moov box for initialization and the moof+mdat boxes for each fragment of MP4 that you generate. You’ll have … Read more
To your question: Is it some kind of a wishful thinking getting HLS & WebGL to play on iOS? Yes, wishful thinking 🙂 The problem/issue/bug is with Apple, not any library. No matter what the JS library, A-Frame, Three, etc, this will always be an issue on any browser in iOS (all browsers on iOS … Read more
Xuggler is a nice opensource Java library that deals with streaming and modifying media on the fly. http://www.xuggle.com/xuggler/ You can either use it with Red5 or if you want complete control, Xuggler has an IContainer class where each instance can be set up to stream media in or out. I’ve been able to restream media … Read more
In newer version of OPENCV there is a built in function can be used to do YUV to RGB conversion cvtColor(src,dst,CV_YUV2BGR_YUY2); specify the YUV format after the underscore, like this CV_YUYV2BGR_xxxx
If you do not need the recording and playback functionality in your app, using off-the-shelf streaming app and player is a reasonable choice. If you do need them to be in your app, however, you will have to look into MediaRecorder API (for the server/camera app) and MediaPlayer (for client/player app). Quick sample code for … Read more
It has something to do with your link and content. Try the following two links: String path=”http://www.ted.com/talks/download/video/8584/talk/761″; String path1=”http://commonsware.com/misc/test2.3gp”; Uri uri=Uri.parse(path1); VideoView video=(VideoView)findViewById(R.id.VideoView01); video.setVideoURI(uri); video.start(); Start with “path1”, it is a small light weight video stream and then try the “path”, it is a higher resolution than “path1”, a perfect high resolution for the mobile … Read more
Finally it works for me. private VideoView videoView; videoView = (VideoView) findViewById(R.id.videoView); Uri video = Uri.parse(“http://www.servername.com/projects/projectname/videos/1361439400.mp4”); videoView.setVideoURI(video); videoView.setOnPreparedListener(new MediaPlayer.OnPreparedListener() { @Override public void onPrepared(MediaPlayer mp) { mp.setLooping(true); videoView.start(); } });