When you ask why a standard is the way it is, there are two possible interpretations of your question: (a) what are the perceived benefits of the design choice that was made, and (b) what was the historical sequence of events that led to this design being adopted over other designs. Clearly, using HTTP-like URIs … Read more
Thanks to Jeremy Lew’s answer and a bit more playing around, I figured out how to remove blank xmlns attributes: pass in the root node’s namespace when creating any child node you want not to have a prefix on. Using a namespace without a prefix at the root means that you need to use that … Read more
You have to declare the dc namespace prefix using an XmlNamespaceManager before you can use it in XPath expressions: XmlDocument rssDoc = new XmlDocument(); rssDoc.Load(rssStream); XmlNamespaceManager nsmgr = new XmlNamespaceManager(rssDoc.NameTable); nsmgr.AddNamespace(“dc”, “http://purl.org/dc/elements/1.1/”); XmlNodeList rssItems = rssDoc.SelectNodes(“rss/channel/item”); for (int i = 0; i < 5; i++) { XmlNode rssDetail = rssItems[i].SelectSingleNode(“dc:creator”, nsmgr); if (rssDetail != null) … Read more
In XML, xmlns declares a Namespace. In fact, when you do: <LinearLayout android:id> </LinearLayout> Instead of calling android:id, the xml will use http://schemas.android.com/apk/res/android:id to be unique. Generally this page doesn’t exist (it’s a URI, not a URL), but sometimes it is a URL that explains the used namespace. The namespace has pretty much the same … Read more
I’d probably be inclined to go with Bartek’s* namespace solution, but a general xpath solution is: //*[local-name()=’ProjectGuid’] **since Bartek’s answer has disappeared, I recommend Teun’s (which is actually more thorough)*
The normal interpretation used by XPath and other specs is that an unprefixed attribute is in no namespace. There are language lawyers who will insist that the namespaces spec doesn’t say that. It says that an unprefixed attribute is in whatever namespace the designer of the vocabulary says it is in. But this interpretation isn’t … Read more
Ahh… nevermind. It’s always the search after the question is posed that yields the answer. My object that is being serialized is obj and has already been defined. Adding an XMLSerializerNamespace with a single empty namespace to the collection does the trick. In VB like this: Dim xs As New XmlSerializer(GetType(cEmploymentDetail)) Dim ns As New … Read more
I also have the following xPath: /List/Fields/Field When I remove the xmlns from my XML the xPath works fine. When it’s in there my xPath finds nothing If you cannot register a namespace binding and cannot use (assuming the registered prefix is “x”): /x:List/x:Fields/x:Field then there is another way: /*[name()=’List’]/*[name()=’Fields’]/*[name()=’Field’]
You can use the local-name() XPath function. Instead of selecting a node like /path/to/x:somenode you can select all nodes and filter for the one with the correct local name: /path/to/*[local-name() = ‘somenode’]
Usually, people use children(). $rss = simplexml_load_string( ‘<?xml version=”1.0″ encoding=”utf-8″?> <rss version=”2.0″ xmlns:moshtix=”http://www.moshtix.com.au”> <channel> <link>qweqwe</link> <moshtix:genre>asdasd</moshtix:genre> </channel> </rss>’ ); foreach ($rss->channel as $channel) { echo ‘link: ‘, $channel->link, “\n”; echo ‘genre: ‘, $channel->children(‘moshtix’, true)->genre, “\n”; }