In Visual Studio 2008 SP1 and later the XML Schema Explorer can create an XML document with some basic sample data: Open your XSD document Switch to XML Schema Explorer Right click the root node and choose “Generate Sample Xml”
You need to create an XmlReaderSettings instance and pass that to your XmlReader when you create it. Then you can subscribe to the ValidationEventHandler in the settings to receive validation errors. Your code will end up looking like this: using System.Xml; using System.Xml.Schema; using System.IO; public class ValidXSD { public static void Main() { // … Read more
I got it. Turns out that it requires \\ to escape the colon. $.get(xmlPath, {}, function(xml) { $(“rs\\:data”, xml).find(“z\\:row”).each(function(i) { alert(“found zrow”); }); }, “xml”); As Rich pointed out: The better solution does not require escaping and works on all “modern” browsers: .find(“[nodeName=z:row]”)
You can do this using XSD 1.1’s Conditional Type Assignment: <?xml version=”1.0″ encoding=”UTF-8″?> <xs:schema xmlns:xs=”http://www.w3.org/2001/XMLSchema” xmlns:vc=”http://www.w3.org/2007/XMLSchema-versioning” elementFormDefault=”qualified” vc:minVersion=”1.1″> <xs:element name=”listOfA”> <xs:complexType> <xs:sequence> <xs:element name=”a” maxOccurs=”unbounded”> <xs:alternative test=”@type = 1″ type=”a1Type”/> <xs:alternative test=”@type = 2″ type=”a2Type”/> </xs:element> </xs:sequence> </xs:complexType> </xs:element> <xs:complexType name=”a1Type”> <xs:sequence> <xs:element name=”name”/> <xs:element name=”surname”/> </xs:sequence> </xs:complexType> <xs:complexType name=”a2Type”> <xs:sequence> <xs:element name=”name”/> <xs:element name=”id”/> … Read more
The Java runtime library supports validation. Last time I checked this was the Apache Xerces parser under the covers. You should probably use a javax.xml.validation.Validator. import javax.xml.XMLConstants; import javax.xml.transform.Source; import javax.xml.transform.stream.StreamSource; import javax.xml.validation.*; import java.net.URL; import org.xml.sax.SAXException; //import java.io.File; // if you use File import java.io.IOException; … URL schemaFile = new URL(“http://host:port/filename.xsd”); // webapp example … Read more
Add one more slash after file:// in the value of xsi:schemaLocation. (You have two; you need three. Think protocol://host/path where protocol is ‘file’ and host is empty here, yielding three slashes in a row.) You can also eliminate the double slashes along the path. I believe that the double slashes help with file systems that … Read more
If you are working on .NET 4.5 project in VS 2012 (or newer), you can just Special Paste your XML file as classes. Copy your XML file’s content to clipboard In editor, select place where you want your classes to be pasted From the menu, select EDIT > Paste Special > Paste XML As Classes
How to link an XSD to an XML document depends upon whether the XML document is using namespaces or not… Without namespaces Use xsi:noNamespaceSchemaLocation to provide a hint as to the XSD to be used: XML <root xmlns:xsi=”http://www.w3.org/2001/XMLSchema-instance” xsi:noNamespaceSchemaLocation=”example.xsd”> <!– … –> </root> XSD <xsd:schema xmlns:xsd=”http://www.w3.org/2001/XMLSchema”> <xsd:element name=”root”> <!– … –> </xsd:element> </xsd:schema> With namespaces … Read more
I use this rule of thumb: An Attribute is something that is self-contained, i.e., a color, an ID, a name. An Element is something that does or could have attributes of its own or contain other elements. So yours is close. I would have done something like: EDIT: Updated the original example based on feedback … Read more