Can’t return a result set in the given context
The answer is to upgrade your php, I’ve just upgraded mine to 5.3.0, and it’s works likes Candy!
The answer is to upgrade your php, I’ve just upgraded mine to 5.3.0, and it’s works likes Candy!
The layout is a view, so the method for assigning variables is the same. In your example, if you were to echo $this->whatever in your layout, you should see the same output. One common problem is how to assign variables that you use on every page to your layout, as you wouldn’t want to have … Read more
fear my google-fu $pdo = new PDO( ‘mysql:host=mysql.example.com;dbname=example_db’, “username”, “password”, array(PDO::MYSQL_ATTR_INIT_COMMAND => “SET NAMES utf8”)); first hit 😉
The problem isn’t with the $name variable but rather with the $_engine variable. It’s currently empty. You need to verify that the path specification to Smarty.class.php is correct. You might try this to begin your debugging: $this->_engine = new Smarty(); print_r($this->_engine); If it turns out that $_engine is correct at that stage then verify that … Read more
Step 1) C:\WINDOWS\system32\drivers\etc\ Open the “hosts” file : 127.0.0.1 localhost 127.0.0.1 test.com 127.0.0.1 example.com Step 2) xampp\apache\conf\extra\httpd-vhosts.conf <VirtualHost *:80> DocumentRoot C:/xampp/htdocs/test/ ServerName www.test.com </VirtualHost> <VirtualHost *:80> DocumentRoot C:/xampp/htdocs/example/ ServerName www.example.com </VirtualHost> Step 3) C:\xampp\apache\conf\httpd.conf. Scroll down to the Supplemental configuration section at the end, and locate the following section (around line 500), Remove the # … Read more
I wrote a function using jQuery and PHP. This is tested, and does work! On the PHP page where you are want to have the timezone as a variable, have this snippet of code somewhere near the top of the page: <?php session_start(); $timezone = $_SESSION[‘time’]; ?> This will read the session variable “time”, which … Read more
Here is another solution which only works in Sql Server 2005 and newer because it uses the except statement. But I share it anyway. If you want to get the records 50 – 75 write: select * from ( SELECT top 75 COL1, COL2 FROM MYTABLE order by COL3 ) as foo except select * … Read more
I would say that you have a problem connecting from PHP to MySQL… Something like PHP trying to find some socket file, and not finding it, maybe ? (I’ve had this problem a couple of times — not sure the error I got was exactly this one, though) If you are running some Linux-based system, … Read more
This question comes up from time to time. There’s no good solution for running a .sql script directly from PHP. There are edge cases where statements common in a .sql script can’t be executed as SQL statements. For example, the mysql tool has builtin commands that are not recognized by the MySQL Server, e.g. CONNECT, … Read more