Welcome to Stack Overflow :). You are on the right way. Your real problem is using a zip. The following configuration is ok and work great for me. It’s an old one (2 years ago), and I’m not sure that match the best practices. But I Know that’s working. This allow me to share some … Read more
JSZip has been updated over the years. Now you can find it on its GitHub repo It can be used together with FileSaver.js You can install them using npm: npm install jszip –save npm install file-saver –save And then import and use them: import JSZip from ‘jszip’; import FileSaver from ‘file-saver’; const zip = new … Read more
Finally I got answer of my question: https://github.com/eligrey/Blob.js/ https://github.com/eligrey/FileSaver.js/ Here is the code: var xhr = new XMLHttpRequest(); xhr.open(“POST”, baseURLDownload + “/service/report/QCPReport”, true); xhr.setRequestHeader(“Content-type”,”application/json”); xhr.setRequestHeader(“Access-Control-Allow-Origin”, “*”); xhr.onreadystatechange = function() { if (xhr.readyState == 4 && xhr.status == 200) { // alert(“Failed to download:” + xhr.status + “—” + xhr.statusText); var blob = new Blob([xhr.response], {type: … Read more
After a little more playing around and reading I was able to figure this out. Here is how you can create a zip file (archive) with multiple files without writing any temporary data to disk: using (var compressedFileStream = new MemoryStream()) { //Create an archive and store the stream in memory. using (var zipArchive = … Read more
I ended up using archiver lib. Works great. Example var file_system = require(‘fs’); var archiver = require(‘archiver’); var output = file_system.createWriteStream(‘target.zip’); var archive = archiver(‘zip’); output.on(‘close’, function () { console.log(archive.pointer() + ‘ total bytes’); console.log(‘archiver has been finalized and the output file descriptor has closed.’); }); archive.on(‘error’, function(err){ throw err; }); archive.pipe(output); // append files … Read more
If you don’t want to install anything but do want to download an SVN or GIT repository, then you can use this: http://downloadsvn.codeplex.com/ I have nothing to do with this project, but I just used it now and it saved me a few minutes. Maybe it will help someone.
let me google this for you -> system.io.packaging+generate+zip first link http://weblogs.asp.net/jongalloway//creating-zip-archives-in-net-without-an-external-library-like-sharpziplib using System; using System.IO; using System.IO.Packaging; namespace ZipSample { class Program { static void Main(string[] args) { AddFileToZip(“Output.zip”, @”C:\Windows\Notepad.exe”); AddFileToZip(“Output.zip”, @”C:\Windows\System32\Calc.exe”); } private static void AddFileToZip(string zipFilename, string fileToAdd, CompressionOption compression = CompressionOption.Normal) { using (Package zip = System.IO.Packaging.Package.Open(zipFilename, FileMode.OpenOrCreate)) { string destFilename = … Read more
You can unzip any files using ant task runner plugin: <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-antrun-plugin</artifactId> <version>1.6</version> <executions> <execution> <id>prepare</id> <phase>validate</phase> <configuration> <tasks> <echo message=”prepare phase” /> <unzip src=”https://stackoverflow.com/questions/3264064/zips/archive.zip” dest=”output/” /> <unzip src=”output/inner.zip” dest=”output/” /> <unzip dest=”output”> <fileset dir=”archives”> <include name=”prefix*.zip” /> </fileset> </unzip> </tasks> </configuration> <goals> <goal>run</goal> </goals> </execution> </executions> </plugin>
As noted elsewhere in the comments, this will only work on a already-created Zip file. The content must also not already exist in the zip file, or an error will be displayed. Here is the working sample code I was able to create based on the accepted answer. You need to link to shell32.lib and … Read more
extractall extracts to the file system, so you won’t get what you want. To extract a file in memory, use the ZipFile.read() method. If you really need the full content in memory, you could do something like: def extract_zip(input_zip): input_zip=ZipFile(input_zip) return {name: input_zip.read(name) for name in input_zip.namelist()}