Sub queries used for the IN clause can’t return multiple columns, so you can’t have SELECT reportsTo, COUNT( * ) AS count inside it. You probably want to join the subquery instead, something like this: SELECT firstName,lastName,temp.count FROM employees INNER JOIN ( SELECT reportsTo, COUNT( * ) AS count FROM employees GROUP BY reportsTo ) … Read more
from field_data_field_date_and_time fdt JOIN node on fdt.<field> = node.uid Without seeing your schema, it is hard to tell what the FK is here.
U can use this: mysqldump -u username -p databasename > filename.sql to export mysql -u username -p databasename < filename.sql to import
update table1 set numberfield = numberfield – 7 if numberfield is 30, then numberfield = 30 – 7, difference will be the new value of the field
You can use GROUP BY keyword for grouping them, your query will become something like this SELECT pm.receiptID , pm.recievedAmount , pd.invono , pd.paidAmount FROM PaymentMaster pm LEFT JOIN PaymentDetail pd ON pd.receiptID = pm.receiptID GROUP BY pd.receiptID
This is what your actual query is SELECT effectiveDate, CASE WHEN note=”REGULAR LOGGED” THEN log END FROM schedules LEFT JOIN timesheet ON schedules.effectiveDate = timesheet.date WHERE schedules.empid=’40’ AND YEAR(effectiveDate) = YEAR(CURDATE()) AND MONTH(effectiveDate) =’1′ GROUP BY effectiveDate. Not sure why you’re using a subquery
select * from persons p join quantity q on p.id = q.people_id join books b on q.product_id = b.id
CREATE VIEW EmpList AS SELECT a.id_user, b.category_province_content, c.category_city_content, d.category_job_content FROM user_detail a INNER JOIN category_province b ON a.detail_province = b.id_category_province INNER JOIN category_city c ON a.detail_city = c.id_category_city INNER JOIN category_job d ON a.detail_job = d.id_category_job To further gain more knowledge about joins and MySQL views, kindly visit the links below: Visual Representation of SQL … Read more
Maybe you can try with something like this: select t.value into @lastValue from test t order by t.date desc limit 1; select t.* from test t where t.value = @lastValue and t.date > (select max(tt.date) from test tt where tt.value <> @lastValue) order by t.date asc limit 1; You can test on this db<>fiddle
SELECT *, NULL AS Field4 FROM TableA WHERE Field1 NOT IN (SELECT Field1 FROM TableB) UNION ALL SELECT * FROM TableB