Regular Expression for ” – ” and characters after [closed]
You can use the regex -(.*), see live demo
regex
Use RegEx to match URL [closed]
Pattern p = new Pattern(“https://mon.contoso.com/mon/call.py?fn=edit&num=(\d+)”) Matcher m = p.matcher(inputEmail); return m.matches() ? m.group(1) : “”; This returns num if it is numeric, otherwise you might want to use \w instead of \d. If you want the whole URL, remove the group() parameter.
PowerShell expression
It takes the contents of a file ‘InputName’, runs it through a regular expression and outputs it to the file ‘OutputName’. The expression takes something in front of a comma, plus the comma itself and concatenates it with something that’s behind a double backslash, some text, a backslash, some text and another backslash. So it … Read more
How does the () and [] come into play with regex?
the r(ege)+x expression will match the letter r followed by one or more sets of the string of letters ege followed by the letter x Possible matches would be “regex”, “regeegex”, “regeegeegex”, and so on. The expression r[ege]+x will match the letter r followed by one or more of any of the letters in the … Read more
string pattern matching using perl regex [closed]
So many things look like a year, especially if unbounded. Since you appear to be looking for the production years of filmed media, we can at least restrict it to the 1900s and 2000s. $str =~ /\b(?:19|20)[0-9]{2}\b/ If the year in which you are interested will always be in parens, the following will be better: … Read more
RegEx for Multi-Words Without Numbers and Any Special Characters
Okay, you want to validate the text: This regex seems to be doing what you want: ^(?=.{1,50}$)(\w+[,.!?&’]?\s?)+$ It will accept a word followed by an optional punctuation and an optional space. The ^(?=.{1,50}$) will control the character limit, here the limit is at least 1 character and max 50 characters The rest is the validation … Read more
Want regex for accepting $,0-9,a-z,+,-,/,*? [closed]
This should match any of the specified characters and no others. /^[$0-9a-z+\-\/*]+$/ Note: the ‘-‘ character needs to be escaped in selection groups like this since it generally signifies a range of possible characters (i.e. a-z or 0-9).
Regular expression to remove fancy apostrophe [closed]
You can use \u to allow any unicode character. If you have a limited set of unsupported characters that can be listed, then you can use character class negation by enclosing the unsupported characters in [^ and ].
How to extract all Yahoo emails from a .CSV file?
grep can read directly from a file, so unless you are intentionally trying to limit the input size the use of head is unnecessary. Likewise, cat is pointless here. The following should work: grep “@yahoo.com” EmailList.csv > file2.csv
regex pattern to find example url from string [closed]
As Marty says, it all depends on which language you are using. You could do it in JavaScript, like so: var myString = “i have a example link:- https://www.google.co.in/search?q=web+service+urls&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a&channel=sb&gfe_rd=cr&ei=ex5iU-6CLMeW8QezvoCgAg i need a regex to extact that full url from text string. thanks!”; var myRegexp = /(http|ftp|https):\/\/[\w-]+(\.[\w-]+)+([\w.,@?^=%&:\/~+#-]*[\w@?^=%&\/~+#-])?/ var match = myRegexp.exec(myString); alert(match[0]); Here’s a demo I … Read more