You are asking how to chain functions in promises.
3) How can I transfer data between them?
4) How can I make the following function depend on its previous result?
Return data (or a promise) for the next function in the chain:
var p2 = p1.then ( function (data) {
var nextData = someFn(data);
return nextData;
});
var p3 = p2.then ( function (nextData) {
var nextData2 = someOtherFn(nextData);
return nextData2;
});
//return for further chaining
return p3;
1) If e.g. checkTokenOnline is not OK, I don’t want to execute the rest functions, how can I quit (exit, break, whatever,..) at this point?
To reject a promise, have your function throw an error. The chain will skip all the .then methods until you supply an error handler.
var p2 = p1.then ( function checkTokenOnline (response) {
if ( isBadFn(response) {
throw error;
} else {
return nextData;
}
}) .then ( someFn
) .then ( someOtherFn
) .catch ( function (error) {
// someFn and someOtherFn skipped
//log error
throw error;
});
//return for further chaining
return p2;
2) How can I set some of them parallel and some of them serial ?
To make two functions run in parallel, make two promises. Use $q.all to wait for them both to complete.
var p1 = $q.when ( fn1() );
var p2 = $q.when ( fn2() );
var p3 = $q.all ( [p1, p2] );
var p4 = p3.then ( function (responseList) {
var response1 = responseList[0];
var response2 = responseList[1];
return something;
}). catch ( function (error) {
//log error
throw error;
});
//return for further chaining
return p4;
Be aware that $q.all is not resilient. If any promise throws an error, the .then method will be skipped and only the first error will go to the .catch method.
The rule of thumb for functional programming is always return something.