Rotating images manually can be a bit of a pain, but here’s how I’ve done it.
private void animateRotation(int degrees, float durationOfAnimation){
long startTime = SystemClock.elapsedRealtime();
long currentTime;
float elapsedRatio = 0;
Bitmap bufferBitmap = carBitmap;
Matrix matrix = new Matrix();
while (elapsedRatio < 1){
matrix.setRotate(elapsedRatio * degrees);
carBitmap = Bitmap.createBitmap(bufferBitmap, 0, 0, width, height, matrix, true);
//draw your canvas here using whatever method you've defined
currentTime = SystemClock.elapsedRealtime();
elapsedRatio = (currentTime - startTime) / durationOfAnimation;
}
// As elapsed ratio will never exactly equal 1, you have to manually draw the last frame
matrix = new Matrix();
matrix.setRotate(degrees);
carBitmap = Bitmap.createBitmap(bufferBitmap, 0, 0, width, height, matrix, true);
// draw the canvas again here as before
// And you can now set whatever other notification or action you wanted to do at the end of your animation
}
This will rotate your carBitmap to whatever angle you specify in the time specified + the time to draw the last frame. However, there is a catch. This rotates your carBitmap without adjusting its position on screen properly. Depending on how you’re drawing your bitmaps, you could end up with your carBitmap rotating while the top-left corner of the bitmap stays in place. As the car rotates, the bitmap will stretch and adjust to fit the new car size, filling the gaps around it with transparent pixels. It’s hard to describe how this would look, so here’s an example rotating a square:
The grey area represents the full size of the bitmap, and is filled with transparent pixels. To solve this problem, you need to use trigonometry. It’s a bit complicated… if this ends up being a problem for you (I don’t know how you’re drawing your bitmaps to the canvas so it might not be), and you can’t work out the solution, let me know and I’ll post up how I did it.
(I don’t know if this is the most efficient way of doing it, but it works smoothly for me as long as the bitmap is less than 300×300 or so. Perhaps if someone knows of a better way, they could tell us!)