This answer expounds on John Black’s helpful answer, so I will repeat some of his answer content in my answer.
The easiest way to resize a marker seems to be leaving argument 2, 3, and 4 null and scaling the size in argument 5.
var pinIcon = new google.maps.MarkerImage(
"http://chart.apis.google.com/chart?chst=d_map_pin_letter&chld=%E2%80%A2|FFFF00",
null, /* size is determined at runtime */
null, /* origin is 0,0 */
null, /* anchor is bottom center of the scaled image */
new google.maps.Size(42, 68)
);
As an aside, this answer to a similar question asserts that defining marker size in the 2nd argument is better than scaling in the 5th argument. I don’t know if this is true.
Leaving arguments 2-4 null works great for the default google pin image, but you must set an anchor explicitly for the default google pin shadow image, or it will look like this:
The bottom center of the pin image happens to be collocated with the tip of the pin when you view the graphic on the map. This is important, because the marker’s position property (marker’s LatLng position on the map) will automatically be collocated with the visual tip of the pin when you leave the anchor (4th argument) null. In other words, leaving the anchor null ensures the tip points where it is supposed to point.
However, the tip of the shadow is not located at the bottom center. So you need to set the 4th argument explicitly to offset the tip of the pin shadow so the shadow’s tip will be colocated with the pin image’s tip.
By experimenting I found the tip of the shadow should be set like this: x is 1/3 of size and y is 100% of size.
var pinShadow = new google.maps.MarkerImage(
"http://chart.apis.google.com/chart?chst=d_map_pin_shadow",
null,
null,
/* Offset x axis 33% of overall size, Offset y axis 100% of overall size */
new google.maps.Point(40, 110),
new google.maps.Size(120, 110));
to give this:
