Here’s a vectorised solution:
res = (a[:, None] == b).all(-1).any(-1)
print(res)
array([ True, True, False, True])
Note that a[:, None] == b
compares each row of a
with b
element-wise. We then use all
+ any
to deduce if there are any rows which are all True
for each sub-array:
print(a[:, None] == b)
[[[ True True]
[False True]
[False False]]
[[False True]
[ True True]
[False False]]
[[False False]
[False False]
[False False]]
[[False False]
[False False]
[ True True]]]