It’s not exactly what you asked for, but it’s pretty close. Put your objects in a named list and use do.call(rbind...)
> do.call(rbind, list(df1 = df1, df2 = df2))
x y
df1.1 1 2
df1.2 3 4
df2.1 5 6
df2.2 7 8
Notice that the row names now reflect the source data.frame
s.
Update: Use cbind
and rbind
Another option is to make a basic function like the following:
AppendMe <- function(dfNames) {
do.call(rbind, lapply(dfNames, function(x) {
cbind(get(x), source = x)
}))
}
This function then takes a character vector of the data.frame
names that you want to “stack”, as follows:
> AppendMe(c("df1", "df2"))
x y source
1 1 2 df1
2 3 4 df1
3 5 6 df2
4 7 8 df2
Update 2: Use combine
from the “gdata” package
> library(gdata)
> combine(df1, df2)
x y source
1 1 2 df1
2 3 4 df1
3 5 6 df2
4 7 8 df2
Update 3: Use rbindlist
from “data.table”
Another approach that can be used now is to use rbindlist
from “data.table” and its idcol
argument. With that, the approach could be:
> rbindlist(mget(ls(pattern = "df\\d+")), idcol = TRUE)
.id x y
1: df1 1 2
2: df1 3 4
3: df2 5 6
4: df2 7 8
Update 4: use map_df
from “purrr”
Similar to rbindlist
, you can also use map_df
from “purrr” with I
or c
as the function to apply to each list element.
> mget(ls(pattern = "df\\d+")) %>% map_df(I, .id = "src")
Source: local data frame [4 x 3]
src x y
(chr) (int) (int)
1 df1 1 2
2 df1 3 4
3 df2 5 6
4 df2 7 8