you could make a numpy array with np.zeros and fill them with your list elements as shown below.
a = [[1, 2, 3], [4, 5], [6, 7, 8, 9]]
import numpy as np
b = np.zeros([len(a),len(max(a,key = lambda x: len(x)))])
for i,j in enumerate(a):
b[i][0:len(j)] = j
results in
[[ 1. 2. 3. 0.]
[ 4. 5. 0. 0.]
[ 6. 7. 8. 9.]]